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# If k^2 = m^2, which of the following must be true?

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Math Expert
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If k^2 = m^2, which of the following must be true?  [#permalink]

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14 Oct 2015, 21:24
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If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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03 May 2016, 08:49
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mkarthik1 wrote:
If k^2 = m^2, which of the following must be true?

A. k = m
B. k = -m
C. k = |m|
D. k = -|m|
E. |k| = |m|

In the above question, Both C and E seem to be correct to me .

The official answer is E. Why should it not be C? can someone please explain.

what is the difference between C and E

Solution:

We are given that k^2 = m^2, and we can start by simplifying the equation by taking the square root of both sides.

√k^2 = √m^2

When we take the square root of a variable squared, the result is the absolute value of that variable. Thus:

√k^2 = √m^2 is |k| = |m|

Note that answer choices A through D could all be true, but each of them would be true only under specific circumstances. Answer choice E is the only one that is universally true.

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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14 Oct 2015, 21:28
1
|k| = |m| suffice the condition of k^2 = m^2.

so ans: E
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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14 Oct 2015, 22:21
2
k^2=m^2
Taking the non negative square root of both sides of the equation ,
|k| = |m|
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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14 Oct 2015, 22:35
1
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

With Even powers of variables the signs can't be predicted about them

Hence, We can't say anything about the sign of k and m being positive or negative
therefore, Option A, B, C and D are ruled out as all these options are hinting towards specific and known sign of k and/or m

For any sign of k and m, their absolute values must be same because k^2 = m^2, therefore, |k| = |m|

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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15 Oct 2015, 00:11
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.

If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Since k^2=m^2 we have 0=k^2 – m^2 =(k-m)*(k+m). So k=m or k=-m.
So only (A) and only (B) cannot be an answer.
The choice (C) tells us that k should be greater than or equal to 0.
Similarly the choice (D) tells us that k should be less than or equal to 0.
So neither (C) nor (D) cannot be the answer.

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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24 Oct 2015, 02:18
1
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

As squaring hides the sign of a number, k^2 will equal m^2 for every possible positive/negative combination of the two values.

The only statement we can make for sure is therefore (E) |k| = |m|.
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If k^2 = m^2, which of the following must be true?  [#permalink]

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11 Apr 2016, 16:32
2
Attached is a visual that should help.
Attachments

Screen Shot 2016-04-11 at 4.31.20 PM.png [ 80.7 KiB | Viewed 18811 times ]

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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06 Sep 2017, 06:29
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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06 Sep 2017, 22:39
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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06 Sep 2017, 22:59
Bunuel wrote:
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.

Hi. Sorry for being not so clear

I meant to say that even powers ^2,^4, etc. always gives positive outcome no matter what the sign of the base is. For example:
(-2)^2= 4
and
(2)^2= 4

So what I inferred is that k^2 and m^2 are positive (no matter what the sign of k and m are). Therefore we can say that |k|=|m|.

Is this good?
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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06 Sep 2017, 23:05
Shiv2016 wrote:
Bunuel wrote:
Shiv2016 wrote:
Hello Bunuel

I inferred that square or even power of a number is always positive. Therefore k^2 and m^2 are positive. So |k|=|m|, no matter what the signs are.
I don't see why in the official guide its mentioned that we need to take root of k^2 and m^2 when we know that ^2 always gives positive number.

Do not follow what you mean bu the point is that $$\sqrt{x^2}=|x|$$, so if we take the square root from k^2 = m^2, we'll get |k| = |m|.

Hi. Sorry for being not so clear

I meant to say that even powers ^2,^4, etc. always gives positive outcome no matter what the sign of the base is. For example:
(-2)^2= 4
and
(2)^2= 4

So what I inferred is that k^2 and m^2 are positive (no matter what the sign of k and m are). Therefore we can say that |k|=|m|.

Is this good?

Apart from knowing that the even roots and absolute values give non-negative result, we should also deduce that from k^2 = m^2 we can get |k| = |m|. Else, what would you say if one of the options were k^4 = |m|? Here both sides are also non-negative, but can we say from k^2 = m^2 that k^4 = |m| is true? No.
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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16 Apr 2018, 10:11
1
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

What does $$k^2 = m^2$$ imply?

Only that |k| = |m|

(A) k = m
Not necessary e.g. k = 5, m = -5

(B) k = −m
Not necessary e.g. k = 5, m = 5

(C) k = |m|
Not necessary e.g. k = -5, m = 5

(D) k = −|m|
Not necessary e.g. k = 5, m = 5

(E) |k| = |m|
Always necessary. Note that absolute values of the two most be equal for the square to be equal. We cannot say anything about their signs though.

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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08 Mar 2019, 19:02
Using the rule that $$\sqrt{x^2}=|x|$$, the equation can be changed to:

$$\sqrt{k^2} = \sqrt{m^2} \rightarrow |k| = |m|$$

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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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03 Jun 2019, 05:14
1
Top Contributor
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

The question asks us what MUST be true. So, if we can find a case where a statement is not true, we can eliminate that answer choice.

So, for example, one solution to the equation (k² = m²) is k = 1 and m = 1
Now let's check the answer choices.
A. k = m. Test: 1 = 1. Works. Keep A.
B. k = -m. Test: 1 = -1. DOESN'T WORK. ELIMINATE B.
C. k = |m|. Test: 1 = |1|. Works. Keep C.
D. k = - |m|. Test: 1 = -|1|. DOESN'T WORK. ELIMINATE D.
E. |k| = |m|. Test: |1| = |1|. Works. Keep E.

Okay, so the correct answer is A, C or E

Let's try another case. Another solution to the equation (k² = m²) is k = -1 and m = 1
Now let's check the remaining answer choices.
A. k = m. Test: -1 = 1. DOESN'T WORK. ELIMINATE A.
C. k = |m|. Test: -1 = |1|. DOESN'T WORK. ELIMINATE C.
E. |k| = |m|. Test: |-1| = |1|. Works. Keep E.

By the process of elimination, the correct answer is E

Cheers,
Brent
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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23 Jun 2019, 06:03
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

If K squared equals an M squared, that means that a K is equal to plus or minus M.

That basically solves the question, because K is not always M;

it's not always minus M; it's not equal to the absolute value of M because K might

be a negative, so negative cannot be something that's positive.

D says that K, which can either be positive or negative, is always equal to

minus of a positive number; well that's not always correct,

and E is the correct one because it says that plus a equals a plus.
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Re: If k^2 = m^2, which of the following must be true?  [#permalink]

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13 Sep 2019, 23:03
Bunuel wrote:
If k^2 = m^2, which of the following must be true?

(A) k = m
(B) k = −m
(C) k = |m|
(D) k = −|m|
(E) |k| = |m|

Kudos for a correct solution.

Given: k^2 = m^2

Asked: Which of the following must be true?

If k^2 = m^2
Taking root on both sides
|k| = |m|

IMO E
Re: If k^2 = m^2, which of the following must be true?   [#permalink] 13 Sep 2019, 23:03
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