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lm-nl = l-9-9l = 18
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| As we have |x| in the equation so we will have two cases | |
| -Case 1: x ≥ 0 => |x| = x => \(x^2 - 7x - 18 = 0\) => \(x^2 − 9x + 2x − 18 = 0\) => x * ( x-9) + 2*(x - 9) = 0 => (x - 9) * (x + 2) = 0 => x = 9 or -2 But condition was x ≥ 0 => x = 9 is a SOLUTION | -Case 2: x < 0 => |x| = -x => \(x^2 + 7x - 18 = 0\) => \(x^2 + 9x - 2x − 18 = 0\) => x * ( x+9) - 2*(x + 9) = 0 => (x + 9) * (x - 2) = 0 => x = -9 or 2 But condition was x < 0 => x = -9 is a SOLUTION |
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