If some of the passengers of the boat Silver Trout board the

Ans is C
let x members on boat Silver Trout and y on Lovely Mary.
A is insufficient as it does not say anything about other boat and so AD ruled out
B is insufficient as same reason above

combine them

0.25x=.50y
x=2y
let straut has 10 member then mary will have 5
clearly this info is sufficient to judge which boat has max numbers of persons.

C is the answer

Suppose i consider 100 persons on ST initially,so this means now there are 75 persons.Now on LM if 100 persons are there then after 50% increase the result will be 150.
On the contrary,if i consider 100 on ST so 75 left and 50 initially on LM then the result will be 75,so 75>75...NO

What am i missing,...?

You cannot consider both to have 100 passengers.

If ST = 100, the 25% = 25. Now, this 25 (according to the second statement) should comprise 50% of LM, so LM = 50. So, if 25 board LM instead of ST each will have 75.

I DONT GET IT

I took an example and it doesnt give any answer

If C is correct then

Lets Assume

1) ST = 5000(Initially)
LM = 500(Initially)

Statement 1 ) will be 5000- 25% of 5000 = 3750 on ST
Statement 2 ) will be 500 + 50% of 500 = 750 on LM

Hence ST wins


2) ST = 500(Initially)
LM = 600(Initially)

Statement 1 ) will be 500- 25% of 500 = 375 on ST
Statement 2 ) will be 600 + 50% of 600 = 900 on LM

Hence LM wins


Can u explain why this example doesnt hold? Am I missing something?

You cannot arbitrarily assume values for BOTH ST and LM. If you assume some value for ST it will define specific value for LM because 1/4 of ST = 1/2 of LM.

Hope it's clear.

Thanks but i hope i dont encounter such question

We need to determine which boat, Silver Trout or Lovely Mary, will have more passengers if some of the passengers of the Silver Trout board the Lovely Mary instead.

Statement One Alone:

The Silver Trout will have 25% fewer passengers than it currently has.

This means the Silver Trout will have 75% of the passengers it currently has; however, without knowing anything about the Lovely Mary, we can’t answer the question. Statement one alone is not sufficient.

Statement Two Alone:

The Lovely Mary will have 50% more passengers than it currently has.

This means the Lovely Mary will have 150% of the passengers it currently has; however, without knowing anything about the Silver Trout, we can’t answer the question. Statement two alone is not sufficient.

Statements One and Two Together:

Let’s let S = the number of passengers the Silver Trout currently has and L = the number of passengers the Lovely Mary currently has. From both statements, we see that 0.25S = 0.50L since when 25% of the passengers on the Silver Trout board the Lovely Mary, the Lovely Mary gains 50% more passengers. Multiply both sides of the equation by 4 and we have S = 2L. Furthermore, if 25% of the passengers on the Silver Trout board the Lovely Mary instead, the Silver Trout will have 0.75S passengers and the Lovely Mary will have 1.5L passengers. However, since S = 2L, 0.75S = 0.75(2L) = 1.5L. We see that the Silver Trout will also have 1.5L passengers, which is the same number of passengers the Lovely Mary will have.

Answer: C

Hello All,

This is the way I understand
A has 400 passengers and 25% left, so it has 300
B is now 50% more than early means 100 is 50% of it early count. So its early count was 200. Now it has 300 and both have same.
Answer C

If both of them have the same number of passengers, we wont be able to answer which is greater

Answer should be E?

@bb@Bunuel@GMATNinjaBunuel
I have the same doubt. Since the question still remains unanswered that which boat has higher number. Can someone please explain why C holds here?

I don't get it. They both have the equal number of passengers. The question is clearly asking - which one has more? Then there is no unique answer. Why is it C. It must be E

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ST = 100 Passengers less 25% = 75 remaining
100-25 = 75

LM = Y + 25 = 1.5Y (+25 passenger from ST, and = 150% or 1.5Y)
25 = 0.5Y
Y = 50
50 + 25 = 75