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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2

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AbdurRakib
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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   23 Jun 2016, 12:07
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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8
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D
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sashiim20
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   24 Jun 2016, 03:37
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Average of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8

Average = Total (sum of numbers)/ number of terms

[ j + (j+5) + (2j-1) + (4j-2) + (5j-1) ] / 5 = 8
[13j + 1 ] / 5 = 8
13j +1 = 8* 5
13j = 40 - 1 = 39
j = 39/13 = 3 .... Answer D.....

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   23 Jun 2016, 12:12
AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8



j + ( j + 5 ) + ( 2j – 1 ) + ( 4j – 2 ) + ( 5j – 1 ) = 40

Or, 13j + 1 = 40

Or, 13j = 39

Or, j = 3

Hence answer will be (D) 3
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   20 Nov 2019, 19:13
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AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8


We can create the equation:

(j + j + 5 + 2j - 1 + 4j - 2 + 5j - 1)/5 = 8

13j + 1 = 40

13j = 39

j = 3

Answer: D
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   20 Nov 2019, 19:13
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AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8


We can create the equation:

(j + j + 5 + 2j - 1 + 4j - 2 + 5j - 1)/5 = 8

13j + 1 = 40

13j = 39

j = 3

Answer: D
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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2 [#permalink] New post   Updated on: 17 May 2021, 07:24
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AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8


GIVEN: he average (arithmetic mean) of 5 numbers \(j\), \(j + 5\), \(2j – 1\), \(4j – 2\), and \(5j – 1\) is \(8\)

We can write: \(\frac{j + (j+5) + (2j-1) + (4j-2)+ (5j-1)}{5}=8\)

Multiply both sides of the equation by \(5\) to get: \(j + (j+5) + (2j-1) + (4j-2)+ (5j-1) = 40\)

Simplify to get: \(13j + 1 = 40\)

Subtract \(1\) from both sides to get: \(13j = 39\)

Divide both sides by \(13\) to get: \(j = \frac{39}{13}=3\)

Answer: D

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Originally posted by BrentGMATPrepNow on 07 Apr 2020, 11:00.
Last edited by BrentGMATPrepNow on 17 May 2021, 07:24, edited 1 time in total.
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j 1, 4j 2 [#permalink] New post   16 May 2022, 07:24
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AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. \(\frac{1}{3}\)
B. \(\frac{7}{13}\)
C. 1
D. 3
E. 8


Take a look at the answer choices. Most of them look really easy to work with. Maybe we can just use PITA (Plugging in the Answers).
Let's try C. Our numbers are 1, 6, 1, 2, 4. Is the average 8? Nope! Do we need something bigger or smaller? Bigger.
Okay, let's try D. Our numbers are now 3, 8, 5, 10, and 14. That sure looks close. Do we even really need to add them up and divide by 5, or can we just tell that E is going to be way too big.

Answer choice D.

ThatDudeKnowsPITA
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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j 1, 4j 2 [#permalink] New post   16 Sep 2022, 22:31
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Given that the Average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8 and we need to find the value of j

================================================================

Theory
    ‣‣‣ Mean or Average = Sum Of All The Numbers) / (Total Number Of Numbers)


================================================================

Average = \(\frac{Sum}{5}\) = \(\frac{j + (j+5) + (2j-1) + (4j-2) + (5j-1)}{8}\) = \(\frac{13j + 1}{5}\) = 8 (given)

=> 13j + 1 = 5*8 = 40
=> 13j = 40 - 1 = 39
=> j = \(\frac{39}{13}\) = 3

So, Answer will be D.
Hope it helps!

Watch the following video to Learn the Basics of Statistics

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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j 1, 4j 2 [#permalink] New post   12 Nov 2022, 05:40
Quick solution:

j+j+2j+4j+5j+5-1-2-1=8*5=40
13j+1=40
13j=39
j=3

Answer: D
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j 1, 4j 2 [#permalink] New post   10 Apr 2024, 05:08
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