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# If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2

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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2  [#permalink]

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23 Jun 2016, 12:07
1
7
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Difficulty:

5% (low)

Question Stats:

87% (01:15) correct 13% (01:07) wrong based on 727 sessions

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If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. $$\frac{1}{3}$$
B. $$\frac{7}{13}$$
C. 1
D. 3
E. 8

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Md. Abdur Rakib

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2  [#permalink]

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23 Jun 2016, 12:12
AbdurRakib wrote:
If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8, what is the value of j ?
A. $$\frac{1}{3}$$
B. $$\frac{7}{13}$$
C. 1
D. 3
E. 8

j + ( j + 5 ) + ( 2j – 1 ) + ( 4j – 2 ) + ( 5j – 1 ) = 40

Or, 13j + 1 = 40

Or, 13j = 39

Or, j = 3

Hence answer will be (D) 3

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2  [#permalink]

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24 Jun 2016, 03:37
Average of 5 numbers j, j + 5, 2j – 1, 4j – 2, and 5j – 1 is 8

Average = Total (sum of numbers)/ number of terms

[ j + (j+5) + (2j-1) + (4j-2) + (5j-1) ] / 5 = 8
[13j + 1 ] / 5 = 8
13j +1 = 8* 5
13j = 40 - 1 = 39
j = 39/13 = 3 .... Answer D.....

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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2  [#permalink]

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30 Sep 2018, 04:01
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Re: If the average (arithmetic mean) of 5 numbers j, j + 5, 2j – 1, 4j – 2   [#permalink] 30 Sep 2018, 04:01
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