Moderator Note:
GMATinsight
If x < 20, How many distinct factors does odd number x have?
1) 16x is divisible by 24
2) 14x is not divisible by 15
Source:
https://www.GMATinsight.comx is odd number less than 20, so we have the entire possible values of x as:- 1, 3, 5, 7, 9, 11, 13, 15, 17, 19.
(1) 24 = 2^3 * 3 and 16 = 2^4.
So 16 has already the required number of 2's but for 16x to be divisible by 24, there needs to be a factor of '3' in the numerator which is coming from x. This means x is divisible by 3. So now the possible values of x are = 3, 9, 15. '3' has two distinct factors (1, 3); 9 has three distinct factors (1, 3, 9). So
not sufficient.
(2) 14 = 2*7 and 15 = 3*5.
So 14 does not have either a 3 or a 5. And since 14x is NOT divisible by 15, it means
x does not contain both 3 & 5 as factors, because in that case it will become divisible by 15. (Please note that x can contain one factor out of 3 or 5 but not both). So as per this the possible values of x are = 1, 3, 5, 7, 9, 11, 13, 17, 19 (only 15 is excluded). So
not sufficient.
Combining both statements, x can still be either '3' or '9'. And while '3' has two distinct factors (1, 3); 9 has three distinct factors (1, 3, 9). So still the data is
not sufficient. Answer should be
E.
(would request you to check the OA, which is mentioned as C)