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Re: In the figure above, if MP bisects ∠NMR, then x = [#permalink]
Bunuel wrote:

In the figure above, if MP bisects ∠NMR, then x =

(A) 80
(B) 90
(C) 100
(D) 110
(E) 120

Attachment:
1.jpg


Asked: In the figure above, if MP bisects ∠NMR, then x =

∠NMR = 180 - (80+40) = 60

∠RMP = 60/2 = 30

x = ∠MPR = 180 - (40 + 30) = 110

IMO D
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Re: In the figure above, if MP bisects ∠NMR, then x = [#permalink]
Let \(y\) be the angle of < NMR
\(\frac{y}{2 }+ x + 40 = 180 \)
\(\frac{y}{2 }+ 180 —x + 80 = 180 \)

\(\frac{y}{2 }+ x = 140\)
\(x —\frac{ y}{2 }= 80\)
—>\( 2x = 220 \)
—>\( x = 110 \)

Answer ( D)

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Re: In the figure above, if MP bisects ∠NMR, then x = [#permalink]
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