tallyho_88
ans is E, although i also think it should be B. Can't seem to figure that out.
E is the correct answer for this question.
Whenever you are given (x-a)(x-b)=0---> you can have the following 3 cases:
1. x-a = 0 and x-b \(\neq\) 0
2. x-b = 0 and x-a \(\neq\) 0
3. x-a = 0 and x-b = 0.
Thus, from (x - 3)(y - 7) = 0 you know that the following 3 cases are possible:
1. x-3 =0 and y-7 \(\neq\) 0
2. x-3 \(\neq\) 0 and y-7 = 0
3. x-3 = 0 and y-7 = 0.
Case 1 gives you a NO for the question asked, is y= 7 and cases 2 and 3 give you a YES for the question asked.
Thus, you get 2 different answers for the question asked. This statement, hence, is NOT sufficient.
Even when you combine the 2 statements, you eliminate case 2 above but cases 1 and 3 still stand. E is thus the correct answer.
Hope this helps.
Im sorry but I am unable to understand your answer. Why is that for every quadratic root, if one is equal to 0, the other is not equal to 0? I thought every quadratic had two roots thus two factors and that would be it. Could you please explain further?
Thank you.