The city of Cortisville has two gas stations, Petrocort and Cortoline.

Answer : A

2.78P + 3.28C = 2.99(P+C)

P____________________C
2.78_______________3.28
_________2.99
0.29_______________0.21

Therefore, 0.21P = 0.29C
or C/P = 21/29

C/(C+P) % = [ 21 / (21+29) ] * 100 % = 42%

P(2.78)----------C(3.28) is 0.5$ apart.

Weighted average is 2.99 which is 0.29$ away from Cortisville and 0.21$ away from Petrocort. So the weightage should be inversely proportional to this. Cortisville sold 0.21/0.50 = 42 % gasoline.

Answer is A

How far is the average from either values ?
so, that is
2.99 - 2.78 = 0.21
2.99 - 3.28 = -0.29

So, for this we can try
x/100 ( 0.21) - y/100 ( 0.29) = 0
now, you can try plugging in values,

here A makes this 0

Solution:

We can let the number of gallons sold at Petrocort = x and the number of gallons sold at Cortoline = y. Thus, the total amount of gas sold that day can be expressed as (x + y).

On a particular day, gasoline at Petrocort was sold for $2.78 per gallon and gasoline at Cortoline was sold for $3.28, and the average price per gallon for gasoline for the entire city that day was $2.99. Thus:

2.78x + 3.28y = 2.99(x + y)

278x + 328y = 299x + 299y

29y = 21x

29y/21 = x

We need to determine what percentage of all gasoline sold was sold at Cortoline, which can be expressed as y/(y+x).

Since x = 29y/21, we can substitute 29y/21 for x in the expression y/(y+x) and we have:

y / (y + 29y/21)

y / (21y/21 + 29y/21)

y / (50y/21)

21y/50y = 21/50 = 42/100 = 42%

Answer: A

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