Hi
VeritasKarishmaI had a query wrt your articles on the made easy series.
Q. IN how many ways can A,B,C,D,E,F be arranged in a circular table provided that A cannot sit next to D or E?
This question is a slight variation in comparison to your question on the Combinations Article 3: Circular Arrangements.
I recon that it is slightly complicated.
Here was my approach:
If only
1. D/E is selected: 2 ways * 6 ways( 3c2 ways of choosing people to be beside A and 2! ways of arranging them) * 2 ways( the other people arrangement)
2. D and E both are selected:
3c2(out of remaining 3 people, 2 are selected)* 2 ways (those 2 people are arranged) * 2 (D,E are arranged in remaining places)
3. A is not selected: 4!
SO total possibilities:
24+ 12+24= 60 ways.
Am i correct in my reasoning ?
and is there any simpler and faster way to do this question?
Looking forward to your reply!
Regards
Nitesh