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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 00:43
VeritasKarishma wrote:
Staphyk wrote:
2 men and 3 women can finish a piece of work in 10 days. while 4 men can do it in 10 days. how many days can 3 men and 3 women take to finish the same work??
Please help me solve this Karishma


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2 men and 3 women finish it in 10 days
4 men (2 men + 2 men) finish it in 10 days

So 3 women are equivalent to 2 men.

Then 3 men and 3 women are equivalent to 3 men and 2 men i.e. 5 men.

Now, 4 men complete the job in 10 days.
So 5 men will take 10*(4/5) = 8 days (fewer days will be taken so multiply by 4/5, the fraction less than 1)

For more on this method, check this post: https://www.veritasprep.com/blog/2015/1 ... made-easy/
Wow! got it ,Thanks very much


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 12:34
| |Brand X | Brand Y|
MilesperGallon | 40 | 36 |
CostperGallon | $0.80 | $0.75 |
The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on $12 worth of brand Y gasoline?
Hello Karishma am totally confused on this question any efficient method?
Thank you


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 05 Dec 2018, 13:22
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 02:32
Staphyk wrote:
| |Brand X | Brand Y|
MilesperGallon | 40 | 36 |
CostperGallon | $0.80 | $0.75 |
The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on $12 worth of brand Y gasoline?
Hello Karishma am totally confused on this question any efficient method?
Thank you


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Here you go: https://gmatclub.com/forum/the-table-ab ... l#p2185231
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 02:37
Staphyk wrote:
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

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You need to find the number of hours required.

When the number of machines go up from 36 to 72, considering everything else constant, will you need more hours or fewer hours? Since the number of machines is more now, you will need less time. More machines will work simultaneously so the work will get completed faster. So you need to multiply 4 by (36/72), the fraction less than 1.

As for orders, from 8 they have gone up to 12 i.e. the work needed to be done has increased. When work to be done increases, keeping everything else constant, will you need more hours or fewer? Since more work has to be done, you need more hours. So you multiply by 12/8, the fraction greater than 1.

4 * (36/72) * (12/8) = 3 hrs

Answer (A)
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 06 Dec 2018, 05:41
VeritasKarishma wrote:
Staphyk wrote:
Again, In a manufacturing plant, it takes 36 machines 4 hours of continuous work to fill 8 standard orders. At this rate, how many hours of continuous work by 72 machines are required to fill 12 standard orders?
This how I solved it
36machines——8orders——4hrs
72machines——12orders—— Xhrs
Now,Xhrs=4*(72/36)*(12/8) =12hrs
But was wrong multiplied by 72/36 since machine increased so fraction (>1) same applies to the orders, Where did my logic go wrong.
Also,when is it appropriate to use the chain rule W1/M*T= W2/M*T
Thank you

Sent from my iPhone using GMAT Club Forum mobile app



You need to find the number of hours required.

When the number of machines go up from 36 to 72, considering everything else constant, will you need more hours or fewer hours? Since the number of machines is more now, you will need less time. More machines will work simultaneously so the work will get completed faster. So you need to multiply 4 by (36/72), the fraction less than 1.

As for orders, from 8 they have gone up to 12 i.e. the work needed to be done has increased. When work to be done increases, keeping everything else constant, will you need more hours or fewer? Since more work has to be done, you need more hours. So you multiply by 12/8, the fraction greater than 1.

4 * (36/72) * (12/8) = 3 hrs

Answer (A)
got it now ,Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 08 Dec 2018, 10:43
Need your help with this question. Please help

https://gmatclub.com/forum/a-parabola-i ... l#p2186783
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 09 Dec 2018, 04:33
https://gmatclub.com/forum/in-the-xy-co ... 47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 00:00
nitesh50 wrote:
https://gmatclub.com/forum/in-the-xy-coordinate-system-what-is-the-slope-of-the-line-47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh


Nitesh,

Distance of a point from a line is assumed to be the perpendicular distance.
If the line passes through the mid-point of two points, its perpendicular distance from both points will be equal (as explained by walker here: https://gmatclub.com/forum/in-the-xy-co ... ml#p452751)
So one way is that the line passes through origin and through the mid-point of PQ.

Alternatively, the line could be passing through origin and parallel to PQ. Then perpendicular distance from P to the line and perpendicular distance from Q to the line will be equal (perpendicular distance between two parallel lines remains same). In that case the line will have a slope of -2/3.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 00:07
vanam52923 wrote:
Need your help with this question. Please help

https://gmatclub.com/forum/a-parabola-i ... l#p2186783


Here: https://gmatclub.com/forum/a-parabola-i ... l#p2187473
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 01:39
VeritasKarishma wrote:
nitesh50 wrote:
https://gmatclub.com/forum/in-the-xy-coordinate-system-what-is-the-slope-of-the-line-47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh


Nitesh,

Distance of a point from a line is assumed to be the perpendicular distance.
If the line passes through the mid-point of two points, its perpendicular distance from both points will be equal (as explained by walker here: https://gmatclub.com/forum/in-the-xy-co ... ml#p452751)
So one way is that the line passes through origin and through the mid-point of PQ.

Alternatively, the line could be passing through origin and parallel to PQ. Then perpendicular distance from P to the line and perpendicular distance from Q to the line will be equal (perpendicular distance between two parallel lines remains same). In that case the line will have a slope of -2/3.



Hi VeritasKarishma

Thank you for the reply.

So just a clarification:
If 2 points are equidistant from a particular line, then can we say that the perpendicular distance of the points to the line is equal?

Regards
Nitesh
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 01:58
Hello Karishma hope you doing great
Please does being solid on only 500-600 level questions enable me get to Quant 45?
Am now at Quant 30 thus a 15points difference


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 04:03
Again , If 6 typists all working at the same rate can complete a document in 4hrs ,how many hours will it take 4 typist to complete the same document ?

Why is it that when solving this using proportion we use rate in the denominator instead of time like this 6/(1/4)=4/x where x is the rate of 4 typist versus using time in the denominator of the proportions which 6/4 =4/x which gives a wrong ans


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 20:15
nitesh50 wrote:
VeritasKarishma wrote:
nitesh50 wrote:
https://gmatclub.com/forum/in-the-xy-coordinate-system-what-is-the-slope-of-the-line-47203.html


Can you help me understand the concept of equidistant points?

What does this exactly mean?
More specifically i cannot understand case 2 mentioned in the discussion.


Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

How is case 2 applicable?
If there are 2 points on a line : A and B.
We draw a parallel line CD.

In this case not every point in the line CD will be equidistant from A and B.


Looking forward to your opinion.

Regards
Nitesh


Nitesh,

Distance of a point from a line is assumed to be the perpendicular distance.
If the line passes through the mid-point of two points, its perpendicular distance from both points will be equal (as explained by walker here: https://gmatclub.com/forum/in-the-xy-co ... ml#p452751)
So one way is that the line passes through origin and through the mid-point of PQ.

Alternatively, the line could be passing through origin and parallel to PQ. Then perpendicular distance from P to the line and perpendicular distance from Q to the line will be equal (perpendicular distance between two parallel lines remains same). In that case the line will have a slope of -2/3.



Hi VeritasKarishma

Thank you for the reply.

So just a clarification:
If 2 points are equidistant from a particular line, then can we say that the perpendicular distance of the points to the line is equal?

Regards
Nitesh


Yes Nitesh, that is correct.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 20:42
Staphyk wrote:
Hello Karishma hope you doing great
Please does being solid on only 500-600 level questions enable me get to Quant 45?
Am now at Quant 30 thus a 15points difference


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Staphyk, you will need to be comfortable with 650 level questions too to be in that score range. Note that GMAT will word the questions in an innovative way so even though you may know the concepts, it will take a bit of effort to actually arrive at them. You will need to learn to identify the concept being tested in different scenarios. So it is a good idea to work with 600 - 700 level questions.
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 10 Dec 2018, 21:35
Staphyk wrote:
Again , If 6 typists all working at the same rate can complete a document in 4hrs ,how many hours will it take 4 typist to complete the same document ?

Why is it that when solving this using proportion we use rate in the denominator instead of time like this 6/(1/4)=4/x where x is the rate of 4 typist versus using time in the denominator of the proportions which 6/4 =4/x which gives a wrong ans


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Look, 6 typists complete it in 4 hrs.
If you have 4 typists, they will take more than 4 hrs (fewer people to do the work).

4 hrs increases by a fraction. What is that fraction? The one by which the number of people have changed.

4 hrs * (6/4) = 6 hrs

Alternatively, if you want to use the work-rate-time formula, try this:

Rate = 6R (because 6 typists work and say rate of each is R)
Time = 4 hrs

Work = Rate*Time = 4*6R = 24R

Now, what happens when we have 4 typists? Rate = 4R
Work is same as before i.e. 24R
Time = ??

Work = Rate*Time

24R = 4R * Time

Time = 6 hrs
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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:21
VeritasKarishma wrote:
Staphyk wrote:
Again , If 6 typists all working at the same rate can complete a document in 4hrs ,how many hours will it take 4 typist to complete the same document ?

Why is it that when solving this using proportion we use rate in the denominator instead of time like this 6/(1/4)=4/x where x is the rate of 4 typist versus using time in the denominator of the proportions which 6/4 =4/x which gives a wrong ans


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Look, 6 typists complete it in 4 hrs.
If you have 4 typists, they will take more than 4 hrs (fewer people to do the work).

4 hrs increases by a fraction. What is that fraction? The one by which the number of people have changed.

4 hrs * (6/4) = 6 hrs

Alternatively, if you want to use the work-rate-time formula, try this:

Rate = 6R (because 6 typists work and say rate of each is R)
Time = 4 hrs

Work = Rate*Time = 4*6R = 24R

Now, what happens when we have 4 typists? Rate = 4R
Work is same as before i.e. 24R
Time = ??

Work = Rate*Time

24R = 4R * Time

Time = 6 hrs
well explained,Thank you


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:23
VeritasKarishma wrote:
Staphyk wrote:
Hello Karishma hope you doing great
Please does being solid on only 500-600 level questions enable me get to Quant 45?
Am now at Quant 30 thus a 15points difference


Sent from my iPhone using GMAT Club Forum mobile app


Staphyk, you will need to be comfortable with 650 level questions too to be in that score range. Note that GMAT will word the questions in an innovative way so even though you may know the concepts, it will take a bit of effort to actually arrive at them. You will need to learn to identify the concept being tested in different scenarios. So it is a good idea to work with 600 - 700 level questions.
very well Karishma ,Thanks for the advice


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Re: Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 11 Dec 2018, 00:50
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math  [#permalink]

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New post 12 Dec 2018, 00:16
Staphyk wrote:
used a time consuming way in solving ,help with an efficient way

A does a work in 8hours,B does the same work in 16hours and C does it in 12hours. A starts working and is joined by B after 2hours,after 3hours of working together ,A leaves and C joins. How much more time will it take to complete the work if B and C continue to work until it’s over?
600 level?


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Hey Staphyk,

Rate of work of A = 1/8
Rate of work of B = 1/16
Rate of work of C = 1/12

Before B and C start working,
A works for 5 hours (2 + 3) and hence does (1/8)*5 = 5/8 of the work.
B works for 3 hrs and hence does (1/16)*3 = 3/16 of the work

So before B and C start working, 5/8 + 3/16 = 13/16 of the work is already over and just 3/16 is left.

Combined rate of B and C = 1/16 + 1/12 = 7/48

Time taken = Work/Rate = (3/16) / (7/48) = 9/7 hrs

I would say 650 level.
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Veritas Prep PS Forum Expert - Karishma - Ask Me Anything about Math &nbs [#permalink] 12 Dec 2018, 00:16

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