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# The table above gives the gasoline costs and consumption rates for a c

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Joined: 01 Sep 2010
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The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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Updated on: 09 Jun 2019, 23:53
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Difficulty:

25% (medium)

Question Stats:

82% (02:43) correct 18% (03:03) wrong based on 320 sessions

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The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand X gasoline than on$12 worth of brand Y gasoline?

(A) 20

(B) 24

(C) 84

(D) 100

(E) 104

Attachment:

renlNEa.jpg [ 37.91 KiB | Viewed 7155 times ]

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Originally posted by carcass on 25 May 2017, 13:06.
Last edited by Bunuel on 09 Jun 2019, 23:53, edited 1 time in total.
Edited the question.
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Joined: 02 Sep 2009
Posts: 58396
Re: The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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25 May 2017, 13:16
carcass wrote:

The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on$12 worth of brand Y gasoline?

(A) 20

(B) 24

(C) 84

(D) 100

(E) 104
Attachment:
renlNEa.jpg

Miles driven on $12 of brand I gasoline = (number of gallons)*(price per gallon) = 12/0.8*40 =12*50 = 600 miles; Miles driven on$12 of brand II gasoline = (number of gallons)*(price per gallon) = 12/0.75*36 = 12*4/3*36 = 576 miles.

Difference = 600 - 576 = 24 miles.

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Re: The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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25 May 2017, 15:09
2
Brand 1
0.8 dollars gives 1 gallon => 12 dollars give 12/0.8 = 15 gallons
1 gallon gives 40 miles => 15 gallons give 600 miles

Brand 2
0.75 dollars gives 1 gallon => 12 dollars give 12/0.75 = 16 gallons
1 gallon gives 36 miles => 16 gallons give 576 miles

Therefore Brand 1 gives 600-576 = 24 miles more
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Re: The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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06 Dec 2018, 03:31
carcass wrote:

The table above gives the gasoline costs and consumption rates for a certain car driven at 50 miles per hour, using each of two brands of gasoline. How many miles farther can the car be driven at this speed on $12 worth of brand I gasoline than on$12 worth of brand Y gasoline?

(A) 20

(B) 24

(C) 84

(D) 100

(E) 104
Attachment:
renlNEa.jpg

The table gives the cost and mileage of two brands of gasoline. Brand X is more expensive but goes for longer distance per gallon.
No of gallons of Brand X gasoline obtained in $12 = 12/0.8 gallons Distance travelled by Brand X in these gallons = (12/0.8) * 40 miles No of gallons of Brand Y gasoline obtained in$12 = 12/0.75 gallons
Distance travelled by Brand X in these gallons = (12/0.75) * 36 miles

$$Difference = (\frac{12}{0.8}) * 40 - (\frac{12}{0.75}) * 36 = 12*4* [\frac{50}{4} - \frac{36}{3}] = 48 * (0.5) = 24 miles$$
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Re: The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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06 Dec 2018, 07:06
Hello Karishma thanks, but please I don’t seem to understand how you go the No. of gallons for Both brands,Kindly throw more light on it

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Re: The table above gives the gasoline costs and consumption rates for a c  [#permalink]

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10 Mar 2019, 22:09
My approach varied from those already mentioned.

Approach:
We know, (Miles/Gallon)(Gallon/$) will give us (Miles/$) - we can use this ratio to see which Brand is more efficient on Miles/$basis and determine the overall difference in Miles for each brand Calculation BrandX Miles/Gallon (Brand x) = 40$ / Gallon (Brand x) = $0.80 (40 miles/ 1 gallon)*(1 gallon /$0.80) = 50 Miles / $1 for BrandX BrandY Miles/Gallon (Brand Y) = 36$/Gallon (Brand Y) = $0.75 (36 miles / 1 gallon) * (1 gallon /$0.75) = 48 Miles / $1 for BrandY Conclusion Therefore, the difference between Brand X and Brand Y is (2 miles /$1)
(2 miles / $1 ) * ($12) = 24 Miles (ANSWER)
Re: The table above gives the gasoline costs and consumption rates for a c   [#permalink] 10 Mar 2019, 22:09
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