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In the xy-coordinate system, what is the slope of the line

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In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post Updated on: 19 Jun 2014, 01:16
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In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (1, 11) and Q = (7, 7)?

A. 2
B. 2.25
C. 2.50
D. 2.75
E. 3

Originally posted by ArvGMAT on 16 Jun 2007, 20:01.
Last edited by Bunuel on 19 Jun 2014, 01:16, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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Re: co ordinate geometry  [#permalink]

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New post 24 Mar 2011, 03:29
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AnkitK wrote:
what is the slope of the line that goes through the origin and is equidistant from the two points p(1,11) and q(7,7)?
A.2
B.2.25
C.2.50
D.2.75
E.3

please provide some tips on co ordinate geometry or some usefull conceptual docs so that i could clear out the concepts of co ordinate geometry.


To get a slope of any line, we need at least 2 points that lie on line. We are already given that line passes through origin so one point is \((0,0)\).

Also, if p and q are equidistant from the line then the mid-point of line segment connecting P and Q lines on the given lines. Mid point is \(((7+1)/2, (11+7)/2)\) or \((4,9)\).

So slope of line is \((9-0)/(4-0) = 9/4 = 2.25\).

Answer B
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 16 Jun 2007, 20:09
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Use midpoint formula to find point equidistant between P and Q; this point must be a part of our line: ((x1+x2)/2, (y1+y2)/2) = (4,9). Slope = rise/run = 9/4 = 2.25
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Re: PS: Line  [#permalink]

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New post 03 Apr 2008, 17:04
B

line: y=ax

1. the line has to pass through the middle point (O) of the segment PQ.
2. the coordinates of the middle point are: (1+(7-1)/2, 7+(11-7)/2) = (4,9)
3. 9=a*4 --> a=2.25
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Re: PS: Line  [#permalink]

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New post 04 Apr 2008, 20:10
1
walker wrote:
B

line: y=ax

1. the line has to pass through the middle point (O) of the segment PQ.
2. the coordinates of the middle point are: (1+(7-1)/2, 7+(11-7)/2) = (4,9)
3. 9=a*4 --> a=2.25



How can you assume that the line will pass through the mid point of PQ.
PQ may not be perpendicular to the line passing through origin.
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Re: PS: Line  [#permalink]

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New post 04 Apr 2008, 22:12
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PM ┴ y=ax, QN ┴ y=ax

PM=QN, QNO=PMO=90°

angle POM = angle QON
angle OPM = angle OQN

So, ∆POM identical with ∆QON and PO=OQ
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What is the slope of the line that goes through the origin a  [#permalink]

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New post 24 Mar 2011, 03:11
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What is the slope of the line that goes through the origin and is equidistant from the two points p(1,11) and q(7,7)?

A. 2
B. 2.25
C. 2.50
D. 2.75
E. 3
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Re: co ordinate geometry  [#permalink]

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New post 24 Mar 2011, 03:52
thnkxx beyondgmatscore.Also i was more interested in some theory concepts.
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Re: co ordinate geometry  [#permalink]

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New post 24 Mar 2011, 06:00
@AnkitK, please look here :

math-coordinate-geometry-87652.html
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Re: co ordinate geometry  [#permalink]

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New post 24 Mar 2011, 18:32
AnkitK wrote:
thnkxx beyondgmatscore.Also i was more interested in some theory concepts.


Most co-ordinate geometry questions become way easier the moment you draw them out... the extra seconds almost always provide a lot of value... Knowing some basic formulas helps and you should be very efficient in drawing lines from their equations, from their slope and a point, from two points etc... Check out the links given below for some concepts on lines, slopes and points....

http://www.veritasprep.com/blog/2010/12 ... he-graphs/
http://www.veritasprep.com/blog/2010/12 ... s-part-ii/
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Re: co ordinate geometry  [#permalink]

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New post 03 Jan 2013, 05:59
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AnkitK wrote:

What is the slope of the line that goes through the origin and is equidistant from the two points p(1,11) and q(7,7)?
A.2
B.2.25
C.2.50
D.2.75
E.3



First, get the middle coordinate between (1,11) and (7,7)...
x = 1 + (7-1)/2 = 4
y = 7 + (11-7)/2 = 9

Second, get the slope of (4,9) and (0,0). m = 0-9 / 0-4 = 9/4 = 2.25

Answer: B
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 04 Jun 2015, 20:44
Hi All.. I went through the explanation given by walker for vshaunak's query.. I still dont find how are we assuming that those points are on opposite sides of the line...What if both are in the same side of the line?
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 05 Jun 2015, 05:36
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ragunandan wrote:
Hi All.. I went through the explanation given by walker for vshaunak's query.. I still dont find how are we assuming that those points are on opposite sides of the line...What if both are in the same side of the line?



Hi Rahghunandan,


You are absolutely CORRECT about your doubt.

However you need to understand the following two points

Case 1) Either a line that is equidistant from the two points must be passing from the the gap between the two points. In this case every point on the line will be equidistant from each of the two given points.

OR

Case 2) The line that is equidistant must be parallel to the line joining the two points (7, 7) and (1, 11). But this case is applicable only when the perpendicular distance of the Line from point is discussed

But in the case 1) the line will have the positive slope and in case 2) the line will have a negative slope [Slope = (11-7) / (1-7) = - (2/3)] and here we have not been given any option of Negative slope. Also the questions doesn't mentioned anything about the perpendicular distance of line from point specifically.

Therefore, We will have to consider case 1 only and find the slope of the line that passes through the gap between two lines and is equidistant from two points.

I hope it clears your doubt!!!
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 17 Jul 2016, 06:02
Hi All,

There are two ways 2 points can be equidistant from a line:

Option1: The line passes through the mid point of the two given points.

In this case find the mid point : X coordinate: (1+7)/2 & Y coordinate: (7+11)/2
Coordinates of the mid point: (4,9)
Now find the slope of the line between the mid point and the origin: ((9-0)/(4-0)) = 2.25


Option 2: The line between the given point P & Q is parallel to a line passing through the origin.


Slope of the line PQ : ((11-7)/(7-1)) =4/6 = 2/3
Slope of parallel lines are the same, hence the slope of the line parallel to PQ will also be 2/3

I am not sure if this is an official question or not but my understanding is that if this were to appear in actual GMAT then question will also provide some information that rules out the option of the line being parallel. E.g : The two line do intersect at some point.

Let me know if you found this useful!

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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 08 Sep 2016, 17:30
1
sgrover18 wrote:
Hi All,

There are two ways 2 points can be equidistant from a line:

Option1: The line passes through the mid point of the two given points.

In this case find the mid point : X coordinate: (1+7)/2 & Y coordinate: (7+11)/2
Coordinates of the mid point: (4,9)
Now find the slope of the line between the mid point and the origin: ((9-0)/(4-0)) = 2.25


Option 2: The line between the given point P & Q is parallel to a line passing through the origin.


Slope of the line PQ : ((11-7)/(7-1)) =4/6 = 2/3
Slope of parallel lines are the same, hence the slope of the line parallel to PQ will also be 2/3

I am not sure if this is an official question or not but my understanding is that if this were to appear in actual GMAT then question will also provide some information that rules out the option of the line being parallel. E.g : The two line do intersect at some point.

Let me know if you found this useful!

Regards,
Shradha



Indeed, this seems to be a fair point that you've pointed out. However, I guess the slope for the parallel line would be (-2/3).
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 14 Jun 2017, 22:48
ArvGMAT wrote:
In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (1, 11) and Q = (7, 7)?

A. 2
B. 2.25
C. 2.50
D. 2.75
E. 3


This question is certainly much easier if you have a solid board with a plane on it

https://www.amazon.com/Manhattan-GMAT-S ... %2F+Marker

Anyways, if we draw out points P and Q on a plane and create a triangle (this step is not really necessary but may help certain test takers) then we can see that height of the triangle is 4 and the length 6. Let our imaginary point be "K"- the x coordinate for this point would exist halfway on the length of the triangle so since our length is 6 half of the length is 3 and 3 spots from the x value of point P, "1" would be 4. The same holds true for the Y value- the y value of our point "K" exists halfway on the length of the triangle- another to think of it is what is the median of the values 7 8 9 10 11- on this logic the y value is 9. Finally, when the question says that the imaginary line passes through the original this simply means that there is no y intercept for the line's equation- in other words any equation of the line would not have the plus or minus part ( example: y= 4x +2- this has a y intercept; y= 5x -2 - this has a y intercept). Knowing this you can simply translate the individual answer choices into equations and solve until you find an equation that satisfies the coordinates (4,9)- for example

Choice E
y= 3x
9= 3(4)
9 does not equal 3(4)

Choice B
9= 2.25x
9= 2 (1/4)x
9= 2(1/4) 4
9= (9/4) 4
9= 36/4

Therefore
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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New post 06 Jul 2017, 17:30
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ArvGMAT wrote:
In the xy-coordinate system, what is the slope of the line that goes through the origin and is equidistant from the two points P = (1, 11) and Q = (7, 7)?

A. 2
B. 2.25
C. 2.50
D. 2.75
E. 3


Since the line is equidistant from P = (1, 11) and Q = (7, 7), it must pass through the midpoint between P = (1, 11) and Q = (7, 7). We can use the midpoint formula:

Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Midpoint = ((1 + 7)/2, (11 + 7)/2)

Midpoint = (4, 9)

Since the line also passes through the origin, (0, 0), the slope is:

Slope = change in y/change in x

(9 - 0)/(4 - 0) = 9/4 = 2.25

Answer: B
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Re: In the xy-coordinate system, what is the slope of the line  [#permalink]

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Re: In the xy-coordinate system, what is the slope of the line   [#permalink] 17 Oct 2018, 17:57
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