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06 Dec 2012, 05:04
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C
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Difficulty:
5%
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Question Stats:
87% (01:07) correct
13%
(01:21)
wrong
based on 1809
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What is the value of b + c ?
(1) ab + cd + ac + bd = 6
(2) a + d = 4
(1) ab + cd + ac + bd = 6
(2) a + d = 4
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06 Dec 2012, 05:10
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What is the value of b + c ?
(1) ab + cd + ac + bd = 6 --> \((ab+bd)+(cd+ac)=6\) --> \(b(a+d)+c(a+d)=6\) --> \((a+d)(b+c)=6\) --> if \(a+d=1\), then \(b+c=6\) but if \(a+d=6\), then \(b+c=1\). Not sufficient.
(2) a + d = 4. Nothing about \(b\) and \(c\). Not sufficient.
(1)+(2) From (1) we have that \((a+d)(b+c)=6\) and from (2) we have that \(a + d = 4\), thus \(4(b+c)=6\) --> \(b+c=1.5\). Sufficient.
Answer: C.
(1) ab + cd + ac + bd = 6 --> \((ab+bd)+(cd+ac)=6\) --> \(b(a+d)+c(a+d)=6\) --> \((a+d)(b+c)=6\) --> if \(a+d=1\), then \(b+c=6\) but if \(a+d=6\), then \(b+c=1\). Not sufficient.
(2) a + d = 4. Nothing about \(b\) and \(c\). Not sufficient.
(1)+(2) From (1) we have that \((a+d)(b+c)=6\) and from (2) we have that \(a + d = 4\), thus \(4(b+c)=6\) --> \(b+c=1.5\). Sufficient.
Answer: C.
General Discussion
24 Apr 2018, 07:57
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Bunuel
pushpitkc hello
can you help me please
sos cant understand the logic of Bunuel`s solution...how from this \(b(a+d)+c(a+d)=6\) he gets this \((a+d)(b+c)=6\)
Alsi \(a+d=1\) how can a+d equal to 1
why a = 0.5 and d = 0.5 ? and he says if \(b+c=6\) ... but first statement says that whole expression is 6 ----> ab + cd + ac + bd = 6
and from combing two statements how can \(b+c=1.5\).
why decimal and not integers and why 1.5 
