NEW HERE? LEARN MORE
closeclose
Last visit was: 02 May 2024, 08:02 It is currently 02 May 2024, 08:02
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

Which of the follow is a set of all possible values of y that satisfy

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
avatar
Alhamdan1995
Intern
Intern
Joined: 12 Apr 2020
Posts: 4
Own Kudos [?]: 7 [5]
Given Kudos: 15
Send PM
Which of the follow is a set of all possible values of y that satisfy [#permalink] New post   16 May 2020, 14:59
5
Kudos
00:00
A
B
C
D
E

Difficulty:

35% (medium)

Question Stats:

65% (01:38) correct 35% (01:46) wrong based on 153 sessions
Hide Show timer Statistics
\(y-13\sqrt{y}+36 = 0\)

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)
ShowHide Answer
Official Answer
E
User avatar
L
chetan2u
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11212
Own Kudos [?]: 32159 [0]
Given Kudos: 298
Send PM
Reviews Badge
Re: Which of the follow is a set of all possible values of y that satisfy [#permalink] New post   16 May 2020, 20:52
Expert Reply
Alhamdan1995 wrote:
\(y-13\sqrt{y}+36 = 0\)

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)


Choices


Since we have \(\sqrt{y}\), y cannot be negative, so you can straight way eliminate the choices B and D.
A) (2,3)
\(y-13\sqrt{y}+36 = 0\) => \(2-13\sqrt{2}+36 = 0\)..NO
B) (4,6)
\(y-13\sqrt{y}+36 = 0\) => \(4-13\sqrt{4}+36 = 0.....40-26=0\)..NO
C) (16,81)
\(y-13\sqrt{y}+36 = 0\) => \(16-13\sqrt{16}+36 = 0....42-13*4=0\)..YES

Algebraic


Let \(\sqrt{y}=x..\)
So, \(x^2-13x+36=0...(x-4)(x-9)=36\)
But, remember we are looking for y, and \(y=x^2...so y=4^2=16....y=9^2=36\)

E
User avatar
L
Kinshook
GMAT Club Legend
GMAT Club Legend
Joined: 03 Jun 2019
Posts: 5346
Own Kudos [?]: 3980 [0]
Given Kudos: 160
Location: India
Schools: HBS '22 CBS '22 Wharton '22
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Send PM
Reviews Badge
Which of the follow is a set of all possible values of y that satisfy [#permalink] New post   17 May 2020, 08:13
Alhamdan1995 wrote:
\(y-13\sqrt{y}+36 = 0\)

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)


\(y-13\sqrt{y}+36 = 0\)

Let \(\sqrt{y}\) be x; y=x^2

\(x^2 - 13x + 36 = 0\)
\(x^2 - 9x - 4x + 36 = 0\)
(x-9)(x-4)=0
x = 9 or x = 4
If x=9; \(\sqrt{y} = 9; y=81\)
If x=4; \(\sqrt{y} = 4; y=16\)

IMO E
User avatar
L
shameekv1989
Director
Director
Joined: 14 Dec 2019
Posts: 829
Own Kudos [?]: 890 [0]
Given Kudos: 354
Location: Poland
Concentration: Entrepreneurship, Strategy
Schools: Cambridge '22 (D) WBS (A$) IIMA PGPX'22 (D) WHU MBA (WD) ISB'22 (D)
GMAT 1: 640 Q49 V27
GMAT 2: 660 Q49 V31
GMAT 3: 720 Q50 V38
GPA: 4
WE:Engineering (Consumer Electronics)
Send PM
GMAT ToolKit User Reviews Badge
Re: Which of the follow is a set of all possible values of y that satisfy [#permalink] New post   17 May 2020, 14:01
Alhamdan1995 wrote:
\(y-13\sqrt{y}+36 = 0\)

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)


\(y−13\sqrt{y}+36=0\)

Let \(\sqrt{y} = x\) => \(y=x^2\)

\(x^2−13x+36=0\)
(x-9)(x-4)=0
x = 9 or x = 4

Therefore,
[m]\sqrt{y} = 9 => y = 81
[m]\sqrt{y} = 4 => y = 16

y = 16,81

Answer - E
User avatar
L
v12345
Senior Manager
Senior Manager
Joined: 01 Mar 2015
Posts: 411
Own Kudos [?]: 914 [0]
Given Kudos: 36
Location: India
Send PM
Re: Which of the follow is a set of all possible values of y that satisfy [#permalink] New post   15 Sep 2021, 08:08
Alhamdan1995 wrote:
\(y-13\sqrt{y}+36 = 0\)

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)


\(y-13\sqrt{y}+36 = 0\)
\(\sqrt{y} \)=4 or 9
y = 16 or 81
Hence, OA is (E).
GMAT Club Bot
gmatclubot
Re: Which of the follow is a set of all possible values of y that satisfy [#permalink]
15 Sep 2021, 08:08
Moderators:
Bunuel
Math Expert
93005 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions