Last visit was: 17 May 2024, 20:08 It is currently 17 May 2024, 20:08
Toolkit
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

# A soccer team played 25% more matches year-on-year in the second year

SORT BY:
Tags:
Show Tags
Hide Tags
Math Expert
Joined: 02 Sep 2009
Posts: 93334
Own Kudos [?]: 624550 [137]
Given Kudos: 81898
Manager
Joined: 09 Apr 2020
Posts: 121
Own Kudos [?]: 284 [12]
Given Kudos: 570
Location: India
Concentration: Strategy, Entrepreneurship
Schools: ISB'22 (D)
GMAT 1: 690 Q49 V35
WE:Engineering (Other)
Current Student
Joined: 07 Sep 2019
Posts: 4
Own Kudos [?]: 7 [7]
Given Kudos: 41
Location: Nepal
GMAT 1: 720 Q50 V38
General Discussion
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Posts: 3137
Own Kudos [?]: 2779 [5]
Given Kudos: 1511
Location: India
GPA: 4
WE:Analyst (Internet and New Media)
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
4
Kudos
=>>> Let matches played in first year = x
=>>> matches won in first year= x*80/100 = 0.8
=>> matches lost in first year = 0.2x

=>>> Matches played in Second year = 25% more than first year = 1.25X
=>>> Matches won in second year(5% increase in second year) = 1.25x*84/100 = 1.05x
Matches lose in second year = =>> 1.25x-1.05x = 0.2x

=>>> Matches played in third year = 4% less than 2nd year = 1.25x*96/100 = 1.2x
=>> Matches won in third year = 1.2x*87.5/100 = 1.05x
=>>> matches lose in third year = 1.2x*12.5/100 = 0.15x

Also, matches lost in third year= 1 less than matches lost in 2nd year
0.15x = 0.20-1
1 = 0.05x
X= 20
Total matches played in first year = 20

Statement 1: Players lost same no. Of matches in year 1&2
Matches lost in year 1 = 0.2x = 0.2*20 = 4
Matches lost in year 2 = 0.2x = 0.2*20 = 4 (True)

Statement 2: The team won the same number of matches in the second year and the third year
Matches won in 2nd year = 1.05x
Matches won in 3rd year = 1.05x
(True)

Statement 3: The team played five more matches in the third year than the first year
Matches played in first year = 20
Matches played in third year= 1.2x = 1.2*20 = 24
Players played only 4 more matches in third year. (False)

Only statement 1 & 2 are correct. But we don't have that option so,

IMO E

Posted from my mobile device
Stern School Moderator
Joined: 26 May 2020
Status:Spirited
Posts: 633
Own Kudos [?]: 539 [1]
Given Kudos: 219
Concentration: General Management, Technology
WE:Analyst (Computer Software)
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
1
Kudos
Bunuel wrote:
A soccer team played 25% more matches year-on-year in the second year of its formation. It won 84% of the matches it played in the second year, which was an improvement of 5% over the percentage of matches won in the first year. In the third year, the team played 4% fewer matches year-on-year but lost only 12.5% of the matches it played, which was one less than the number of matches lost by the team in the second year. Which of the following statements must be correct?

I. The team lost the same number of matches in the first yea and the second year
II. The team won the same number of matches in the second year and the third year
III. The team played five more matches in the third year than the first year

A. I only
B. II only
C. III only
D. I, II and III
E. None of the above

B , IMO

Question
------------------------1st Year-----------------------------------------2nd year------------------------------------------- 3rd year

Played-------------------x---------------------------------------------1.25x-------------------------------------------0.96 *1.25 x

Won----------------0.84 *1.25 x / 1.05 ---------------------------0.84 *1.25 x--------------------------------------NA-----------

Loss----------------- NA-------------------------------------------0.16 *1.25 x------------------0.125 * 0.96 * 1.25 x = 0.16 *1.25 x -1

0.125 * 0.96 * 1.25 x = 0.16 *1.25 x -1
1 = 1.25 x (0.16 – 0.125 *0.96 ) => x = 1 / 1.25 * 0.04 = 20

Now lets fill the table with X = 20

------------------------1st Year-----------------------------------------2nd year--------------------------------------- 3rd year

Played-------------------x=20-----------------------------------------1.25x=25-------------------------------0.96 *1.25 x = 24

Won----------------0.84 *1.25 x / 1.05 = 20----------------0.84 *1.25 x = 21-------------------------------24-3= 21

Loss----------------- 0 ----------------------------------0.16 *1.25 x = 4------------0.125 * 0.96 * 1.25 x = 0.16 *1.25 x -1 = 3

I. The team lost the same number of matches in the first year and the second year – No
II. The team won the same number of matches in the second year and the third year – Correct
III. The team played five more matches in the third year than the first year – No

Hence B.

Originally posted by HoneyLemon on 07 Jun 2020, 04:53.
Last edited by HoneyLemon on 07 Jun 2020, 05:22, edited 1 time in total.
Stanford School Moderator
Joined: 11 Jun 2019
Posts: 113
Own Kudos [?]: 56 [2]
Given Kudos: 181
Location: India
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
2
Kudos
Quote:
Now it is given that there was an improvement of 5% over the percentage of matches won in the first year. So 84% is with 5% of improvement from first year. So we can deduce that team won 80% of the matches in first year.

Can someone please explain this? Why is this 80% and not 79%?
Manager
Joined: 09 Apr 2020
Posts: 121
Own Kudos [?]: 284 [2]
Given Kudos: 570
Location: India
Concentration: Strategy, Entrepreneurship
Schools: ISB'22 (D)
GMAT 1: 690 Q49 V35
WE:Engineering (Other)
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
2
Kudos
davidbeckham wrote:
Quote:
Now it is given that there was an improvement of 5% over the percentage of matches won in the first year. So 84% is with 5% of improvement from first year. So we can deduce that team won 80% of the matches in first year.

Can someone please explain this? Why is this 80% and not 79%?

Here GMAT is playing with the words. Read this carefully.

there was an "improvement of 5% over the percentage" of matches won in the first year.

It does not mean increase of 5%, rather it means 5% improvement. Let say first year team won X% of matches. It is given that in second year it won 84% so equation becomes 1.05X = 84. Which gives us X = 80%.

I hope now it is clear.

Posted from my mobile device

Originally posted by Thelionking1234 on 17 Jul 2020, 17:24.
Last edited by Thelionking1234 on 26 Jul 2020, 09:51, edited 1 time in total.
Senior Manager
Joined: 04 May 2020
Status:What goes round comes around, so does Kudos.
Posts: 262
Own Kudos [?]: 236 [1]
Given Kudos: 295
Location: India
GPA: 4
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
1
Kudos
There are so many seemingly Bulky Equations and solutions making things even more complex.

Since we know in second year, They played 25% more which is 5/4 times what they played in first year.

You can assume
First year = 80
=> Second year = 100 or $$( 80*5/4)$$

Second
won 84: lost 16

Second year winning percentage is 5 percent better.

Hence in 1st year
1.05x = 84.
X = 80 ( or else you know 4 is 5% of 80 anyway)
80% won
First : Won = 64
Lost = 16

Third :
Played 96.
Lost = $$96*12.5$$
$$=> 96*1/8= 12$$
Lost = 12
Won = 84

Posted from my mobile device

Statement 1 and 2 are true.
IMO E
Director
Joined: 29 Apr 2019
Status:Learning
Posts: 748
Own Kudos [?]: 583 [0]
Given Kudos: 49
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
Correct Option E
1st Condition - True
2nd Condtion - True
3rd Condition - False
Hence option - E
Attachments

1.jpg [ 63.3 KiB | Viewed 2069 times ]

Manager
Joined: 20 Feb 2022
Posts: 63
Own Kudos [?]: 15 [0]
Given Kudos: 88
Location: India
Concentration: Finance, Other
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
chetan2u - Can you please clarify the below doubt?
The question mentions "which was an improvement of 5% over the percentage of matches won in the first year" and I think everybody has used 80%. How should we infer that they are talking about 5% increase in the % (80%*1.05) or flat increase in the % itself (79%+5%)? How do we write the latter?

Thank you
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11264
Own Kudos [?]: 32571 [1]
Given Kudos: 306
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
1
Kudos
Sonia2023 wrote:
chetan2u - Can you please clarify the below doubt?
The question mentions "which was an improvement of 5% over the percentage of matches won in the first year" and I think everybody has used 80%. How should we infer that they are talking about 5% increase in the % (80%*1.05) or flat increase in the % itself (79%+5%)? How do we write the latter?

Thank you

It is given that improvement of 5% OVER the previous year.
OVER clearly means you are taking base as previous year %. Invariably, most of the question would mean but in case it has to mention the latter, I believe words could be: It was 84% in the second year, a % that was 5% more as compared to % of last year.
Manager
Joined: 01 Jan 2014
Posts: 219
Own Kudos [?]: 94 [0]
Given Kudos: 456
Location: United States (MI)
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]

Bunuel wrote:
A soccer team played 25% more matches year-on-year in the second year of its formation. It won 84% of the matches it played in the second year, which was an improvement of 5% over the percentage of matches won in the first year. In the third year, the team played 4% fewer matches year-on-year but lost only 12.5% of the matches it played, which was one less than the number of matches lost by the team in the second year. Which of the following statements must be correct?

I. The team lost the same number of matches in the first yea and the second year
II. The team won the same number of matches in the second year and the third year
III. The team played five more matches in the third year than the first year

A. I only
B. II only
C. III only
D. I, II and III
E. None of the above

Are You Up For the Challenge: 700 Level Question

­I read through the thread and I am confused. Why do some people say A and B both are correct? I got only B correct. I am thrown off by "It won 84% of the matches it played in the second year, which was an improvement of 5% over the percentage of matches won in the first year." What does this mean?
Moreover, I believe we should simply calculate for Win and Loss, no Tie etc. This is a question that I'll probably guess and forget in the exam, but here it is for the practice and concept.

­
Attachments

IMG_0536.jpg [ 1.68 MiB | Viewed 911 times ]

Tutor
Joined: 16 Oct 2010
Posts: 14891
Own Kudos [?]: 65335 [0]
Given Kudos: 431
Location: Pune, India
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
Bunuel wrote:
A soccer team played 25% more matches year-on-year in the second year of its formation. It won 84% of the matches it played in the second year, which was an improvement of 5% over the percentage of matches won in the first year. In the third year, the team played 4% fewer matches year-on-year but lost only 12.5% of the matches it played, which was one less than the number of matches lost by the team in the second year. Which of the following statements must be correct?

I. The team lost the same number of matches in the first yea and the second year
II. The team won the same number of matches in the second year and the third year
III. The team played five more matches in the third year than the first year

A. I only
B. II only
C. III only
D. I, II and III
E. None of the above

Are You Up For the Challenge: 700 Level Questions

Since everything is in percentages, assume values. Instinctively, I took 100 for first year but a 25% increase and then 84% is too much of calculation. So instead I will take second year matches played as 100.

First year matches played is 80 (so that when increased by 25%, it becomes 100).
Say they won x% matches.

Second year matches played is 100
Matches won = 84% = 84
Matches lost = 16

A 5% increase on x% gave 84%. x% is likely to be 80%. Why? Since base is smaller, the amount of increase will be a bit lower than 5 to give 5%.
Check - 4/80 is 5%. Correct.
So they won 80% matches in first year.
Matches won in first year is 64
Matches lost is 16

In third year, they played 4% fewer matches so they played 96 matches.
They lost 12.5% ie 1/8 of these. So they lost 12 and won 84 in third year.

I. The team lost the same number of matches in the first year and the second year

Correct. 16 each.

II. The team won the same number of matches in the second year and the third year

Correct. 84 each

III. The team played five more matches in the third year than the first year

Incorrect. It played 16 more.

Posted from my mobile device
Manager
Joined: 13 Dec 2023
Status:Applying in R1 of 2024 to t15
Affiliations: University of Tennessee
Posts: 123
Own Kudos [?]: 98 [0]
Given Kudos: 41
Location: United States (CO)
Concentration: Strategy, Finance
GMAT Focus 1:
605 Q76 V84 DI80
GPA: 3.62
WE:Analyst (Consumer Products)
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
why is it E? B should be the correct answer right??? When you do the math with test number of 100 games, it equals out to 105 wins each for year 2 and year 3.
Manager
Joined: 19 Dec 2021
Posts: 108
Own Kudos [?]: 44 [0]
Given Kudos: 5
Location: Viet Nam
GPA: 3.55
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
Win rate of Y2 is 84%, which is 5% more than the percentage of Y1
Win rate of Y1 is x%
=> 84% = $$\frac{105}{100}$$ * x%
=> 84% = $$\frac{21}{20}$$ * x%
=> x = ­ 84% * $$\frac{20}{21}$$ = 80%

Total played                      Won                          Lost                           Draw

Y1   200 (supposedly)               160 (80% win rate)     [_]                             [_]

Y2   250 (25% more than Y1)    210 (84% win rate)     31 (1 more than Y3)    9 = (250-210-31)

Y3   240 (4% fewer than Y2)     [_]                                30 (lost 12.5%)        [_]

I. The team lost the same number of matches in the first year and the second year
We don't know the number of matches lost in Y1
=> No

II. The team won the same number of matches in the second year and the third year
We don't know the number of matches won in year
=> No

III. The team played five more matches in the third year than the first year
Team played 250 matches in Year 2 and 240 matches in Y3
=> No
­
Re: A soccer team played 25% more matches year-on-year in the second year [#permalink]
Moderators:
Math Expert
93334 posts
Senior Moderator - Masters Forum
3137 posts