It is currently 15 Dec 2017, 04:28

Decision(s) Day!:

CHAT Rooms | Wharton R1 | Stanford R1 | Tuck R1 | Ross R1 | Haas R1 | UCLA R1


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Box W and Box V each contain several blue sticks and red

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Manager
Manager
avatar
Joined: 01 Nov 2007
Posts: 147

Kudos [?]: 451 [0], given: 0

GMAT ToolKit User
Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 29 Jan 2008, 14:34
8
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

71% (01:37) correct 29% (01:56) wrong based on 241 sessions

HideShow timer Statistics

Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less that the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

(A) 3
(B) 6
(C) 12
(D) 18
(E) 24
[Reveal] Spoiler: OA

Kudos [?]: 451 [0], given: 0

1 KUDOS received
Director
Director
avatar
Joined: 01 Jan 2008
Posts: 617

Kudos [?]: 207 [1], given: 1

Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 29 Jan 2008, 14:49
1
This post received
KUDOS
JCLEONES wrote:
Box W and Box V each contain several blue sticks and red sticks,
and all of the red sticks have the same length. The length of each red
stick is 19 inches less that the average length of the sticks in Box W
and 6 inches greater than the average length of the sticks in Box V.
What is the average (arithmetic mean) length, in inches, of the sticks
in Box W minus the average length, in inches, of the sticks in Box V?
(A) 3
(B) 6
(C) 12
(D) 18
(E) 24


length(red) = average(W) - 19
length(red) = average(V) + 6

average(W) - average(V) = 6+19=25 -> closest to E

Kudos [?]: 207 [1], given: 1

SVP
SVP
avatar
Joined: 28 Dec 2005
Posts: 1543

Kudos [?]: 189 [0], given: 2

Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 29 Jan 2008, 19:26
concur with E ... closest to 25.

W has x red and y blue. V has a red and b blue

length(x)=length(a) = length(x)*x + length(y)*y / x+y + 19 = length(a)*a+length(b)*b/a+b + 6

shifting terms, we get the first term minus second term is 6+19=25

Kudos [?]: 189 [0], given: 2

2 KUDOS received
Manager
Manager
avatar
Joined: 17 Aug 2009
Posts: 227

Kudos [?]: 301 [2], given: 25

Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 10 Dec 2009, 11:30
2
This post received
KUDOS
1
This post was
BOOKMARKED
Why do test Makers unnecessarily complicate matters????

Simply put, let the length of each red stick be R

Now R = Average length of sticks in Box W – 18------------- (1)
Also, R = Average length of sticks in Box V +6---------------(2)

Avg. length of sticks in Box W - 18 = Avg. length of sticks in Box V + 6
Avg. length of sticks in Box W - Avg. length of sticks in Box V = 24-----which is what we had to calculate

Hence E

Kudos [?]: 301 [2], given: 25

1 KUDOS received
Intern
Intern
avatar
Joined: 17 Oct 2011
Posts: 20

Kudos [?]: 76 [1], given: 10

Location: Taiwan
GMAT 1: 590 Q39 V34
GMAT 2: 680 Q47 V35
Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 19 Feb 2012, 05:51
1
This post received
KUDOS
The right number is not 19 but 18.
"The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V"

Kudos [?]: 76 [1], given: 10

Expert Post
2 KUDOS received
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 42620

Kudos [?]: 135707 [2], given: 12706

Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 19 Feb 2012, 11:00
2
This post received
KUDOS
Expert's post
1
This post was
BOOKMARKED
wizard wrote:
The right number is not 19 but 18.
"The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V"


For the question with 19 and 6 inches correct answer is 25:
{Average lengths of sticks in W} - 19 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;

{Average W}-19={Average V}+6 --> {Average W}-{Average V}=25.

For the question with 18 and 6 inches correct answer is 24:
{Average lengths of sticks in W} - 1 = Length of red;
{Average lengths of sticks in V} + 6 = Length of red;

{Average W}-18={Average V}+6 --> {Average W}-{Average V}=24.

Hope it's clear.
_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135707 [2], given: 12706

Manager
Manager
User avatar
B
Status: IF YOU CAN DREAM IT, YOU CAN DO IT
Joined: 03 Jul 2017
Posts: 177

Kudos [?]: 8 [0], given: 14

Location: India
Concentration: Finance, International Business
Re: Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 14 Nov 2017, 07:05
this is how i solved this question . So let the number of blue sticks in Box W be BW and red sticks be RW and let the number of blue sticks in Box V be BV and red sticks be RV. Also let the length of each red stick be x and the length of each blue stick be y.
Therefore as per the statements given , x= RW(x)+ BW(y) / RW+BW - 18
and x = 6+ RV(x)+BV(y) / RV+BV
Therefore the question is asking to find the difference between the two.So RW(x)+BW(y)/BW+RW - RV(x)+BV(y)/ BV+RV (that is the difference between the averages of the two boxes), So (x+18)-(x-6)= x+18-x+6=24 . The answer is E

Kudos [?]: 8 [0], given: 14

Manager
Manager
User avatar
B
Status: love the club...
Joined: 24 Mar 2015
Posts: 213

Kudos [?]: 21 [0], given: 472

Box W and Box V each contain several blue sticks and red [#permalink]

Show Tags

New post 03 Dec 2017, 15:54
JCLEONES wrote:
Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less that the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

(A) 3
(B) 6
(C) 12
(D) 18
(E) 24


with respect to red

W
+18

and

V
-6

= 18 - (-6)
=24

thanks
:cool:

Kudos [?]: 21 [0], given: 472

Box W and Box V each contain several blue sticks and red   [#permalink] 03 Dec 2017, 15:54
Display posts from previous: Sort by

Box W and Box V each contain several blue sticks and red

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.