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If Vivica typed a document at an average rate that was greater than 90

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If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 19 Jan 2018, 09:31
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Question Stats:

61% (01:36) correct 39% (01:39) wrong based on 142 sessions

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If Vivica typed a document at an average rate that was greater than 90 words per minute, did it take her less than one hour to type this document?

(1) Vivica typed the first three-quarters of the words in the document in 42 minutes.
(2) Vivica's rate of words per minute was constant for the duration of the document.

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Re: If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 19 Jan 2018, 09:41
Bunuel wrote:
If Vivica typed a document at an average rate that was greater than 90 words per minute, did it take her less than one hour to type this document?

(1) Vivica typed the first three-quarters of the words in the document in 42 minutes.
(2) Vivica's rate of words per minute was constant for the duration of the document.


Hi..Bunuel, great to see you both at the chat and here at forum...
so let me also put in my bit..

ans will be C...
statement I gives us what work has been done .. but we do not know how much is the document..
insuff
statement ii tells the speed is constant..
insuff

combined..
you can calculate the exact time
suff
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If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 19 Jan 2018, 09:45
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Bunuel wrote:
If Vivica typed a document at an average rate that was greater than 90 words per minute, did it take her less than one hour to type this document?

(1) Vivica typed the first three-quarters of the words in the document in 42 minutes.
(2) Vivica's rate of words per minute was constant for the duration of the document.


Statement 1: we have no information regarding the rate at which the remaining \(\frac{1}{4}\) document is typed. Hence Insufficient

Statement 2: we know the rate is same through the job but the value of rate and the word quantity is not given. Insufficient

Combining 1 & 2: we know the rate is constant, so if \(\frac{3}{4}\) words are typed in \(42\) minutes

then whole i.e \(1\) will be typed in \(\frac{42*4}{3}\) minutes. Sufficient

Option C
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Re: If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 05 Feb 2018, 08:50
chetan2u wrote:
Bunuel wrote:
If Vivica typed a document at an average rate that was greater than 90 words per minute, did it take her less than one hour to type this document?

(1) Vivica typed the first three-quarters of the words in the document in 42 minutes.
(2) Vivica's rate of words per minute was constant for the duration of the document.


Hi..Bunuel, great to see you both at the chat and here at forum...
so let me also put in my bit..

ans will be C...
statement I gives us what work has been done .. but we do not know how much is the document..
insuff
statement ii tells the speed is constant..
insuff

combined..
you can calculate the exact time
suff


The document is actually 5040 words.

90 wpm x 42 minutes = 3780 words typed in 42 minutes

3780 words represents 3/4 of the work

3/4(x) = 3780

(3780 x 4)/3
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Re: If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 14 Feb 2018, 02:18
Hi!
The information - 90 wpm is redundant, right?
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Re: If Vivica typed a document at an average rate that was greater than 90  [#permalink]

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New post 14 Feb 2018, 06:33
shubhajit wrote:
Hi!
The information - 90 wpm is redundant, right?


Hi

Yes, here we can find the answer C without making use of '90 words per minute' data.
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Re: If Vivica typed a document at an average rate that was greater than 90 &nbs [#permalink] 14 Feb 2018, 06:33
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If Vivica typed a document at an average rate that was greater than 90

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