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In the expression above, a, b, and c are different numbers and each is
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Updated on: 06 Jun 2017, 07:39

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(a/b)/c In the expression above, a, b, and c are different numbers and each is one of the numbers 3, 4, or 7. What is the least possible value of the expression?

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Re: In the expression above, a, b, and c are different numbers and each is
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06 Jun 2017, 01:41

GMATinsight wrote:

(a/b)/c In the expression above, a, b, and c are different numbers and each is one of the numbers 3, 4, or 7. What is the least possible value of the expression? (A) 21/4 (B) 3/28 (C) 4/21 (D) 7/12 (E) 3/7

A is improper fraction hence it is bigger than all other options. Check all other options. B) 3/28 = 0.107 C) 4/21 = 0.190 D) 7/12 = 0.583 E) 3/7 = 0.428

Least possible value of (a/b)/c is \(\frac{3}{28}\) = 0.107. Answer B...

Re: In the expression above, a, b, and c are different numbers and each is
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06 Jun 2017, 04:37

GMATinsight wrote:

(a/b)/c

In the expression above, a, b, and c are different numbers and each is one of the numbers 3, 4, or 7. What is the least possible value of the expression? (A) 21/4 (B) 3/28 (C) 4/21 (D) 7/12 (E) 3/7

Re: In the expression above, a, b, and c are different numbers and each is
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06 Jun 2017, 08:51

Top Contributor

GMATinsight wrote:

(a/b)/c In the expression above, a, b, and c are different numbers and each is one of the numbers 3, 4, or 7. What is the least possible value of the expression?

So, we want to minimize the value of a/(bc) To do so, we must MINIMIZE the numerator (a) and MAXIMIZE the denominator (bc) So, let a = 3, and let b = 4 and c = 7

Re: In the expression above, a, b, and c are different numbers and each is
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08 Jun 2017, 15:44

GMATinsight wrote:

(a/b)/c In the expression above, a, b, and c are different numbers and each is one of the numbers 3, 4, or 7. What is the least possible value of the expression?

(A) 21/4 (B) 3/28 (C) 4/21 (D) 7/12 (E) 3/7

We can simplify the given expression:

(a/b)/c = a/(bc)

To make a fraction’s value as small as possible, we need to make the numerator as small as possible and the denominator as large as possible.

Thus, we can let a = 3, b = 4, and c = 7, and we have:

3/28

Answer: B
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Re: In the expression above, a, b, and c are different numbers and each is
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24 Jun 2017, 15:40

\((a/b)/c\)

a, b and c can be any of these three different numbers. - 3, 4 & 7.

We have to find the least possible value of the equation.

So, we must increase the denominator - means we will take bigger numbers to the denominator and smaller ones to numerator.

after simplying above quation we get

\(\frac{a}{bc}\)

a - minimum value \(= 3\), b and c can take remaining values = \(4 * 7\) (or vice a versa) \(= 28\)

We get \(\frac{3}{28}\)

Hence, Answer is B

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Re: In the expression above, a, b, and c are different numbers and each is
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27 Jan 2019, 21:31

Maximize the denominator in order to get the least value of the fraction. Hence, choose the largest of the three numbers i.e. 7 as the value of the overall denominator (c), and next largest value as the value of b.

(3/4)/7 = 3/28 (Option B)
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Re: In the expression above, a, b, and c are different numbers and each is
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27 Jan 2019, 21:31