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Senior Manager  B
Joined: 17 Sep 2013
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Concentration: Strategy, General Management
GMAT 1: 730 Q51 V38 WE: Analyst (Consulting)
Is a an integer?  [#permalink]

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Difficulty:   45% (medium)

Question Stats: 57% (00:59) correct 43% (00:59) wrong based on 667 sessions

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Is a an integer?

(1) a^3 is an integer.
(2) The cube root of a is an integer.

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Re: Is a an integer?  [#permalink]

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thalcantero wrote:
I still don't get why the first statement is insufficient, could someone explain a little further please? Is a an integer?

(1) a^3 is an integer --> a will be an integer if a^3 is a perfect cube, for example, if a^3 is 0, 1, 8, 27, ... but a can also be the cube root from an integer (which is not a perfect cube), for example if a is $$\sqrt{2}$$, $$\sqrt{3}$$, $$\sqrt{4}$$, ... Not sufficient.

(2) The cube root of a is an integer. $$\sqrt{a}=integer$$ --> $$a=integer^3=integer$$. Sufficient.

Hope it's clear.
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Senior Manager  B
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Re: Is a an integer?  [#permalink]

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2
From Statement 1, a could definitely be an integer since any integer cubed will remain an integer. However, a could also be a cube root. If we cube the cube root of 2, the result is 2. Insufficient. Statement 2, however, guarantees that a must be an integer. a = cubert(a) * cubert(a) * cubert(a). If cubert(a) is an integer, then a must be an integer as well. Thus, the correct answer is B
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Re: Is a an integer?  [#permalink]

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I still don't get why the first statement is insufficient, could someone explain a little further please? Current Student B
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Re: Is a an integer?  [#permalink]

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Thanks a lot for the explanation, it is pretty clear now.
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Re: Is a an integer?  [#permalink]

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Bunuel : I am not able to understand this part of your explanation ''but a can also be the cube root from an integer (which is not a perfect cube), for example if a is 2√3, 3√3''.
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narendran1990 wrote:
Bunuel : I am not able to understand this part of your explanation ''but a can also be the cube root from an integer (which is not a perfect cube), for example if a is 2√3, 3√3''.

Not sure what to explain... If a is $$\sqrt{2}$$, $$\sqrt{3}$$, or $$\sqrt{4}$$, then a^3 will be 2, 3, or 4 respectively.
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Re: Is a an integer?  [#permalink]

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I am not good with some basics of exponents, so I couldn't understand your explanation. It is clear now.

Thank you.
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GMAT 1: 540 Q38 V26 Re: Is a an integer?  [#permalink]

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Bunuel wrote:
narendran1990 wrote:
Bunuel : I am not able to understand this part of your explanation ''but a can also be the cube root from an integer (which is not a perfect cube), for example if a is 2√3, 3√3''.

Not sure what to explain... If a is $$\sqrt{2}$$, $$\sqrt{3}$$, or $$\sqrt{4}$$, then a^3 will be 2, 3, or 4 respectively.

Only this made me understand the problem Thanks!
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Re: Is a an integer?  [#permalink]

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JusTLucK04 wrote:
Is a an integer?

(1) a^3 is an integer.
(2) The cube root of a is an integer.

The answer is B

From Statement 1 it is clear that cube of an integer is always an integer but when we take cube of root(2) then also the result will be integer hence insufficient
Statement 2 on the other hand clearly tells us that the cube root of the number is always an integer .Therefore the number a must be an integer hence sufficient .
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Re: Is a an integer?  [#permalink]

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arvind910619 wrote:
JusTLucK04 wrote:
Is a an integer?

(1) a^3 is an integer.
(2) The cube root of a is an integer.

The answer is B

From Statement 1 it is clear that cube of an integer is always an integer but when we take cube of root(2) then also the result will be integer hence insufficient
Statement 2 on the other hand clearly tells us that the cube root of the number is always an integer .Therefore the number a must be an integer hence sufficient .

hello, it seems that practice is the only way to ensure that we will not make any mistakes in thinking, is that so?
it is because I have not worked on any math problems for a long time. When I try to find the answer, I always worry that I will miss something.
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Re: Is a an integer?  [#permalink]

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JusTLucK04 wrote:
Is a an integer?

(1) a^3 is an integer.
(2) The cube root of a is an integer.

From 1
We dont know the orientation of a, what if it was

a = 3^1/3, we satisfy 1, but answer to the question will be a No
a = 3, we satisfy 1, and answer the question a Yes

From 2
The cube root of a is an integer.

This will always be true, a^1/3 = 3^ (3*1/3) = Yes

B
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Many of life's failures happen with people who do not realize how close they were to success when they gave up. Re: Is a an integer?   [#permalink] 31 Jan 2019, 07:39
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