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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
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ksha wrote:
Is \(m > n\) ?

(1) \(n – m + 2 > 0\)
(2) \(n – m – 2 > 0\)


We can rephrase the question: "Is \(m – n > 0\) ?" 

(1) INSUFFICIENT:  If we solve this inequality for \(m – n\), we get \(m – n < 2\).  This does not answer the question "Is \(m – n > 0\) ?".
(2) SUFFICIENT:  If we solve this inequality for \(m – n\), we get \(m – n < -2\).  This answers the question "Is \(m – n > 0\) ?" with an absolute NO.

The correct answer is B.
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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
Hi Bunuel cud you pls put some light on this questionBunuel
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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
monty6000 wrote:
Hi Bunuel cud you pls put some light on this questionBunuel



Hello Monty6000,

Is there anything in the solution provided or question that you did not understand??

Please post your query or how did you approach the question or what do you think the answer should be and why
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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
Is m > n ?

(1) n – m + 2 > 0
m -n < 2 NS.
(2) n – m – 2 > 0
m-n < -2 => m-n < 0 => m < n..
Suff.
B.
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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
Is m > n ?

(1) n – m + 2 > 0

For m=2, n=1, the condition of (1) will hold and we can say that m>n

For m=2, n=3, the condition of (1) will hold, but we can say that m<n

Hence, (1) alone is not sufficient.


(2) n – m – 2 > 0

When we simplify this expression, we get n> (m+2).
This means that for any value of m, n will always be 2 units higher that m. In other words, n>m always. using (2) alone, we have a definite answer.

Hence, (B) is the right answer choice.
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Re: Is m > n ? (1) n – m + 2 > 0 (2) n – m – 2 > 0 [#permalink]
Could anyone tell me where I went wrong?

(1) n-m+2 > 0 --> n-m>-2 NS.
(2) n-m-2 > 0 --> n-m>2 N.S.

Combining 1 and 2 and Adding the two statements, 2n - 2m > 0 or 2(n-m) >0 or n>m. Gives a sufficient NO. So I went for C. But OA is B.
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Re: Is m > n ? (1) n m + 2 > 0 (2) n m 2 > 0 [#permalink]
ksha wrote:
Is m > n ?

(1) n – m + 2 > 0
(2) n – m – 2 > 0


target is m>n
or say m-n>0
#1
n-m+2>0
n>m-2
if m=0 then n>-2
so n can be 0 we get no to target or n = -1 we get yes to target
insufficient
#2
n>m+2
m=0 then n has to be >2 and its always > m as well
no to target and sufficient
option B
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Re: Is m > n ? (1) n m + 2 > 0 (2) n m 2 > 0 [#permalink]
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Re: Is m > n ? (1) n m + 2 > 0 (2) n m 2 > 0 [#permalink]
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