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Is x > 1? (1) 2x + 5 > 2 - x (2) |x - 12| = 12 - 3x

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Joined: 16 Oct 2016
Posts: 219
Location: India
Concentration: General Management, Healthcare
GMAT 1: 640 Q40 V38
GMAT 2: 680 Q48 V35
GPA: 3.05
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Is x > 1? (1) 2x + 5 > 2 - x (2) |x - 12| = 12 - 3x  [#permalink]

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New post 04 Feb 2019, 07:01
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Question Stats:

20% (01:32) correct 80% (01:27) wrong based on 19 sessions

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Is x > 1?

(1) 2x + 5 > 2 - x
(2) |x - 12| = 12 - 3x

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Joined: 05 Feb 2016
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Re: Is x > 1? (1) 2x + 5 > 2 - x (2) |x - 12| = 12 - 3x  [#permalink]

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New post 04 Feb 2019, 07:15
fitzpratik wrote:
Is x > 1?

1. 2x+5 > 2-x
2. |x-12| = 12-3x


From 1 3x>-3, x>-1 ,Not sufficient
From 2 if x>12
then ,x-12=12-3x =>x=6 not possible since x>12
if x<12
then 12-x=12-3x, x=0 sufficient
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Re: Is x > 1? (1) 2x + 5 > 2 - x (2) |x - 12| = 12 - 3x  [#permalink]

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New post 04 Feb 2019, 07:16
fitzpratik wrote:
Is x > 1?

1. 2x+5 > 2-x
2. |x-12| = 12-3x


from 1
When we solve the inequulity
we will get x > -1
which will answer the question as No, when x =0
which will answer the question as Yes, when x =2

from 2
x-12 = 12-3x or -x+12 = 12-3x
x = 6 or x = 0

Now we did get 2 values here, but will they both satisfy the modulus, lets see
At x = 6
|6-12| = 12-18
6 ! = 6, Not a valid value

At x = 0
12 = 12, True

So only one value comes out,which will answer the question as No

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Re: Is x > 1? (1) 2x + 5 > 2 - x (2) |x - 12| = 12 - 3x   [#permalink] 04 Feb 2019, 07:16
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