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Re: M08-34 [#permalink]
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RahulS90 wrote:
While the option D is correct, I think there is a slight error in your interpretation of option B

You have written 0.2x - 0.2 y = 40

This is wrong because the question says "40 more" and not "just 40"

Hence
0.2x - 0.4 y = 40 + (0.12x - 0.12y)

0.08 x - 0.08 y = 40
Hence x - y = 500 and not 200

Please let me know if I am wrong


Yes, you are wrong.

(2) If the interest were 20% then in one year Jules would have earned $40 more than Jim from bond M.

If the interest were 20% then in one year Jules would have earned 0.2x
If the interest were 20% then in one year Jules would have earned 0.2y

Jules would have earned $40 more than Jim, so 0.2x = 0.2y + 40, which is the same as 0.2x - 0.2y = 40.
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Re: M08-34 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M08-34 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M08-34 [#permalink]
Hi Bunnel
Could you post similar questions to this
and if you could also post theory related to this. It would be very helpful

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Re: M08-34 [#permalink]
While the option D is correct, I think there is a slight error in your interpretation of option B

You have written 0.2x - 0.2 y = 40

This is wrong because the question says "40 more" and not "just 40"

Hence
0.2x - 0.4 y = 40 + (0.12x - 0.12y)

0.08 x - 0.08 y = 40
Hence x - y = 500 and not 200

Please let me know if I am wrong
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Re: M08-34 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re: M08-34 [#permalink]
Hi Bunuel, if in the second option it was given that the 20% increase is over two years then would we have multiplied the same equation with two? If not, how should we solve that?
Bunuel wrote:
Official Solution:


Question: \(x-y=?\)

(1) In one year Jules earned $24 more than Jim from bond M. \(0.12x-0.12y=24\). Reduce by 0.12: \(x-y=200\). Sufficient.

(2) If the interest were 20% then in one year Jules would have earned $40 more than Jim from bond M. Basically the same type of information as above: \(0.2x-0.2y=40\), reduce by 0.2: \(x-y=200\). Sufficient.

Important note: when two quantities are increased (decreased) by the same percent their difference also increase (decrease) by the same percent. For example if you increase 100 and 150 by 20% to 120 and 180 respectively, then their difference will also increase by the same 20% from 50 to 60.


Answer: D
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Re: M08-34 [#permalink]
Expert Reply
davidbeckham wrote:
Hi Bunuel, if in the second option it was given that the 20% increase is over two years then would we have multiplied the same equation with two? If not, how should we solve that?
Bunuel wrote:
Official Solution:


Question: \(x-y=?\)

(1) In one year Jules earned $24 more than Jim from bond M. \(0.12x-0.12y=24\). Reduce by 0.12: \(x-y=200\). Sufficient.

(2) If the interest were 20% then in one year Jules would have earned $40 more than Jim from bond M. Basically the same type of information as above: \(0.2x-0.2y=40\), reduce by 0.2: \(x-y=200\). Sufficient.

Important note: when two quantities are increased (decreased) by the same percent their difference also increase (decrease) by the same percent. For example if you increase 100 and 150 by 20% to 120 and 180 respectively, then their difference will also increase by the same 20% from 50 to 60.


Answer: D


If (2) were If the interest were 20% (instead of 12%) then in two years Jules would have earned $40 more than Jim from bond M, then we'd have: \((1.2^2x -x) - (1.2^2y - y) = 40\) (interest earned = final sum - investment = 1.2*1.2*x - x).
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Re: M08-34 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re M08-34 [#permalink]
I think this is a high-quality question and I agree with explanation.
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Re M08-34 [#permalink]
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