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On her way home from a business trip, Janice remembers that she needs

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On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 28 Jul 2017, 00:26
2
3
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

47% (01:45) correct 53% (02:03) wrong based on 70 sessions

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On her way home from a business trip, Janice remembers that she needs to buy each of her three children a souvenir. At the airport shop, the only items left are two hats, two t-shirts, two posters, and two keychains. How many combinations can she select from if she wants each child to receive a different item?

A. 24
B. 32
C. 40
D. 48
E. 56

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Re: On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 28 Jul 2017, 00:46
Bunuel wrote:
On her way home from a business trip, Janice remembers that she needs to buy each of her three children a souvenir. At the airport shop, the only items left are two hats, two t-shirts, two posters, and two keychains. How many combinations can she select from if she wants each child to receive a different item?

A. 24
B. 32
C. 40
D. 48
E. 56


to buy from two hats, two t-shirts, two posters, and two keychains

Every child has to get different item so we need 3 out of 4 items first in 4C3 = 4 ways

Now from every item there are 2 ways to pick the item for one child

i.e. Total bways to pick items for children = 4C3 *2 *2 *2 = 4*8 = 32

Answer: Option B
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Re: On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 28 Jul 2017, 01:00
Bunuel wrote:
On her way home from a business trip, Janice remembers that she needs to buy each of her three children a souvenir. At the airport shop, the only items left are two hats, two t-shirts, two posters, and two keychains. How many combinations can she select from if she wants each child to receive a different item?

A. 24
B. 32
C. 40
D. 48
E. 56


Hat T-shirt Poster Keychain

4C3 = 4
3! = 6
6*4=24

Alternatively
If A gets Hat
B gets T-shirt then last one has 4 options = 4
B has three options so total will be 12

Now A has 4 options
So the total becomes 12*4 = 48

Two answers...
Please help me understand what i am missing
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On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 02 Aug 2017, 16:58
GMATinsight wrote:
Bunuel wrote:
On her way home from a business trip, Janice remembers that she needs to buy each of her three children a souvenir. At the airport shop, the only items left are two hats, two t-shirts, two posters, and two keychains. How many combinations can she select from if she wants each child to receive a different item?

A. 24
B. 32
C. 40
D. 48
E. 56


to buy from two hats, two t-shirts, two posters, and two keychains

Every child has to get different item so we need 3 out of 4 items first in 4C3 = 4 ways

Now from every item there are 2 ways to pick the item for one child

i.e. Total bways to pick items for children = 4C3 *2 *2 *2 = 4*8 = 32

Answer: Option B


So you're assuming there is 2 different t shirts, 2 different key chains, 2 different posters and 2 different hats? I agree with your solution if that is the case. I assumed they were the same there there are 4 ways to select item 1, 3 ways to select item 2 and 2 ways to select item 3. Or 4X3X2 or 24.

I think Veritas should be clearer on if they mean 2 different items or not. There questions are getting a lot **** as I move through the practice tests. Why the hell not right 2 different hats, 2 different posters. I don't get how the whole question is writing poorly.
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Re: On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 02 Aug 2017, 18:57
SamBoyle wrote:
GMATinsight wrote:
Bunuel wrote:
On her way home from a business trip, Janice remembers that she needs to buy each of her three children a souvenir. At the airport shop, the only items left are two hats, two t-shirts, two posters, and two keychains. How many combinations can she select from if she wants each child to receive a different item?

A. 24
B. 32
C. 40
D. 48
E. 56


to buy from two hats, two t-shirts, two posters, and two keychains

Every child has to get different item so we need 3 out of 4 items first in 4C3 = 4 ways

Now from every item there are 2 ways to pick the item for one child

i.e. Total bways to pick items for children = 4C3 *2 *2 *2 = 4*8 = 32

Answer: Option B


So you're assuming there is 2 different t shirts, 2 different key chains, 2 different posters and 2 different hats? I agree with your solution if that is the case. I assumed they were the same there there are 4 ways to select item 1, 3 ways to select item 2 and 2 ways to select item 3. Or 4X3X2 or 24.

I think Veritas should be clearer on if they mean 2 different items or not. There questions are getting a lot **** as I move through the practice tests. Why the hell not right 2 different hats, 2 different posters. I don't get how the whole question is writing poorly.


Giving "Two different shirts" would have been awesome however the question always mentions if the objects are identical so in absence of it you should consider them different and it's not an assumption...
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On her way home from a business trip, Janice remembers that she needs  [#permalink]

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New post 02 Aug 2017, 21:24
I guess that's just a GMAT quirk that I'll remember.

I read the items as being the same and found that to be the difficulty of the question. If you told me you had 2 baseballs, I'd assume they were the same baseball and wouldn't need you to tell me you had 2 identical baseballs. I really see no logic in the GMAT thinking it's necessary to say when things are identical but not to say when things are different. That's an esoteric logic system and I believe has only shown up on Veritas not the GMAT itself.

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On her way home from a business trip, Janice remembers that she needs   [#permalink] 02 Aug 2017, 21:24
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