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The average (arithmetic mean) of four packages is 4 pounds. If the wei

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The average (arithmetic mean) of four packages is 4 pounds. If the wei [#permalink]

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New post 08 Jan 2018, 06:35
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A
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E

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The average (arithmetic mean) of four packages is 4 pounds. If the weight of the first package is x, and each package weighs two more pounds than the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 9
B. 10
C. 12
D. 13
E. 14
[Reveal] Spoiler: OA

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Re: The average (arithmetic mean) of four packages is 4 pounds. If the wei [#permalink]

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New post 08 Jan 2018, 06:55
first number =x
next three terms = x+2, x+4,x+6
Sum of terms = 4*4 =16 (average =4)
POE
Assume numbers 1,3,5,7
Sum =16
A) 9 (1+3+5)
B) 10 (7+3)
C) 12 (7+5)
D) 13 (7+5+1)
E) 14 not possible

Ans. E
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Re: The average (arithmetic mean) of four packages is 4 pounds. If the wei [#permalink]

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New post 08 Jan 2018, 08:05
Bunuel wrote:
The average (arithmetic mean) of four packages is 4 pounds. If the weight of the first package is x, and each package weighs two more pounds than the previous package, which of the following CANNOT be the total weight, in pounds, of any combination of the packages?

A. 9
B. 10
C. 12
D. 13
E. 14


4*4 = x + ( x + 2 ) + ( x + 4 ) + ( x + 6 )

So, 4x + 12 = 16

Or, 4x = 4

So, x = 1

So, The weights are 1 , 3 , 5 , 7

Further as worked out by mandeey , answer must be (E)
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Re: The average (arithmetic mean) of four packages is 4 pounds. If the wei   [#permalink] 08 Jan 2018, 08:05
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