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Bunuel
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let d=length of race
r=B's rate
because times of A and B are equal,
then d/(5r/4)=(d-7)/r
d=35 meters
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Another approach would be to let speed of B be 4 and speed of A = 4 * 1.25 = 5

Now B starts at 7 then move 4s

7,11,15,19,23,27,31,35

A starts at 0,5,10,15,20,25,30,35

Answer choice D.

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Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters

Let the length of the race be \(d\), B runs \((d-7)\) meters and A runs \(d\) meters, in \(s\) mph and \(1.25s\) mph respectively.

\(time = \frac{distance}{speed}\)

Time taken by A = \(\frac{d}{1.25s}\)

Time taken by B = \(\frac{d-7}{s}\)

Since the race was a dead heat \(\frac{d}{1.25s} = \frac{d-7}{s}\)

\(ds = 1.25ds - 8.75s\)

\(d = 1.25d - 8.75\)

\(d = \frac{8.75}{0.25} = 35\).
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Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters

If B's usual rate of running the race is 4x, A's rate will be 5x

Since the distances covered by both of them are equal provided A covers
7m less, we can equate the distances. So, \(5x = 4x + 7\) -> \(x = 7\)

Therefore, the total length of the race is \(5x\) = 35 meters(Option D)
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Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters


\(\frac{x}{125} = \frac{x-7}{100}\)

\((x-7)125 = 100x\)

\(125x-100x=875\)

\(25x=875\)

\(x = 35\)
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Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters

Let the length of the race be represented by d and let the rate of runner B be represented by r. Since A runs 25% faster than B, the rate of A is 1.25r.

Since the times are the same, we can create the equation:

time for runner A = time for runner B

d/1.25r = (d - 7)/r

rd = 1.25r(d - 7)

d = 1.25d - 8.75

8.75 = 0.25d

35 = d

Answer: D
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Alternative Approach.

Using the Gap formula, we Suppose that B is 7 meters ahead of A when starting the race. It means that
Meeting time = Gap/(Va-Vb) = 7/(1.25-1) = 28 meters.

Now the problem says that A is ahead of B at the moment of ending the race by 7 meters. So the race distance is = 28 + 7 = 35

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Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters

A can cover d in t time. B can cover d-7 in t time.
So here time t is constant for A and B, let d be the distance for track-

d/125 = (d-7)/100

d= 35
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I saw it this way.
The speed is 25% more, which is 1/4 more. Therefore the distance covered will be 1/5th less in the same time. 1/5th is given to us as 7. So the actual distance will be 35.

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Ratio of speeds = 5:4
There is a difference of 1 metre for each time interval they run and at same time A bridges 7 metres gap.
It means that 5*7:4*7 = 35:28 is the distances travelled giving us 7 metre gap.
Thus total length = 35.
Bunuel
A runs 25% faster than B and is able to allow B a lead of 7 meters to end a race in dead heat. What is the length of the race?

A. 10 meters
B. 15 meters
C. 25 meters
D. 35 meters
E. 45 meters
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