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03 Jan 2019, 04:54
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A
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Difficulty:
5%
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Question Stats:
85% (01:17) correct
15%
(02:28)
wrong
based on 173
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A certain company places a six-symbol code on each of their products. The first two symbols are one of the letters A–E and the last four symbols are digits. If repeats are allowed on both letters and numbers, how many such codes are possible?
(A) 250000
(B) 350000
(C) 450000
(D) 550000
(E) 600000
(A) 250000
(B) 350000
(C) 450000
(D) 550000
(E) 600000
UB001
Joined: 26 Dec 2018
Last visit: 10 Apr 2022
Posts: 106
Given Kudos: 91
Location: India
Schools: Mannheim"20 Smurfit "20 NUS '21 NTU '20
Given :
A six-symbol code of which the first two symbols are one of the letters A–E
and the last four symbols are digits.
repeats are allowed both letters and numbers,
Question: how many such odes are possible?
AANNNN
Let us denote the code by AANNNN, where A for Alphabets from A to E, and N for numbers from 0 to 9.
Alphabets are 5 (A, B, C, D, E) & Numbers are 10 (0 to 9)
Since repeats are allowed alphabets can take 5 positions each for the first two letters, and numbers can take 10 positions each for the 4 positions each for the next four remaining letters of the code.
Therefore,
A A N N N N
5 x 5 x 10 x 10 x 10 x 10 = 250,000
Answer Option A is correct.
A six-symbol code of which the first two symbols are one of the letters A–E
and the last four symbols are digits.
repeats are allowed both letters and numbers,
Question: how many such odes are possible?
AANNNN
Let us denote the code by AANNNN, where A for Alphabets from A to E, and N for numbers from 0 to 9.
Alphabets are 5 (A, B, C, D, E) & Numbers are 10 (0 to 9)
Since repeats are allowed alphabets can take 5 positions each for the first two letters, and numbers can take 10 positions each for the 4 positions each for the next four remaining letters of the code.
Therefore,
A A N N N N
5 x 5 x 10 x 10 x 10 x 10 = 250,000
Answer Option A is correct.
UB001
Joined: 26 Dec 2018
Last visit: 10 Apr 2022
Posts: 106
Given Kudos: 91
Location: India
Schools: Mannheim"20 Smurfit "20 NUS '21 NTU '20
03 Jan 2019, 06:24
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