Given:
• A milkman mixed 4 liters of water with 10 liters of milk.
• He boiled one-fourth of this mixture till the water content in it halved.
o Then he added it to the remaining mixture.
To find:
• The proportion of milk in the mixture after the process.
Approach and Working out:
The volume of solution after mixing 4 liters of water with 10 liters of milk =14L
¾ of the solution that is kept as it is:
• Volume of solution that was not taken out = 14 - 3.5 = 10.5L.
o Milk and water in solution is in the ratio of 10:4 = 5:2
• Hence, quantity of milk in ¾ of the solution = \(\frac{5}{7} \)× 10.5 =7.5L
o Quantity of water in ¾ of the solution = \(\frac{2}{7}\) × 10.5 =3 L
¼ of this solution that is taken out.
• Volume of solution taken out = 14/4 = 3.5 L.
o Milk and water in 3.5L solution is in the ratio of 10:4 = 5:2
• Hence, quantity of milk in ¼ of the solution = \(\frac{5}{7} \) × 3.5 =2.5L
o Quantity of water in ¼ of the solution = \(\frac{2}{7}\) × 3.5 =1 L
This 3.5L of the mixture is boiled until the water quantity becomes half.
• New quantity of milk = Old quantity of milk = 2.5 L
• New quantity of water = ½ of 1 L = 0.5L
Now, this mixture is added to the original solution again.
• Total quantity of milk = 7.5 + 2.5 = 10L
• Total quantity of water = 3+0.5 = 3.5L
The proportion of milk after the process = \(\frac{10}{13.5}\) =20/27
Hence, option B is the correct answer.
Correct Answer: Option B