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14 Oct 2021, 06:45
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (02:11) correct
27%
(02:15)
wrong
based on 92
sessions
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Admission to a certain ballet school is very competitive. 3/8 of all applicants are male. 3/4 of all applicants are rejected in the first round including 2/3 of all male applicants. What fraction of applicants remaining after the first round are male?
A. 1/32
B. 1/4
C. 1/2
D. 3/4
E. 8/9
A. 1/32
B. 1/4
C. 1/2
D. 3/4
E. 8/9
14 Oct 2021, 07:33
Kudos
Bookmarks
Bunuel
Say, total 24
Male 24*3/8 = 9
Female 24-9 = 15
Total elimination 24*3/4 = 18
Total Passed 24-18 = 6
Male failed 9*2/3 = 6
Male passed 9-6 = 3
Fraction 3/6 = 1/2
Ans. C
Correct Option C
Let the applicants = 80.
\(\frac{3}{4}\) applicants are rejected = \(\frac{3}{4}\) * 80 = 60.
\(\frac{2}{3}\) of all of the male applicants rejected out of 60 = (\(\frac{2}{3}\)) * 60 = 40.
\(\frac{Total-Number-of-male-application-rejected }{ The-total-number-applicants}\) = \(\frac{40}{80}\) = \(\frac{1}{2}\) = The answer is (C).
Posted from my mobile device
Let the applicants = 80.
\(\frac{3}{4}\) applicants are rejected = \(\frac{3}{4}\) * 80 = 60.
\(\frac{2}{3}\) of all of the male applicants rejected out of 60 = (\(\frac{2}{3}\)) * 60 = 40.
\(\frac{Total-Number-of-male-application-rejected }{ The-total-number-applicants}\) = \(\frac{40}{80}\) = \(\frac{1}{2}\) = The answer is (C).
Posted from my mobile device
