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A man needs to travel a certain distance. He travels certain distance by car and the rest by train. Car travel costs him $12 per km and travelling by train costs him $8 per km. If the total amount spent on car travel was x% of the total amount spent on whole journey and the total distance traveled by car was y% of the total distance covered, what is the value of y in terms of x?

A. x/(100-x)

B. 200x/(300-x)

C. 300x/(200-x)

D. 200x/(x-300)

E. None of these

Assume values.

Cost by car = $12/km
Cost by train = $8/km

So say 1 km was travelled by car and 1 km by train. So total 2 kms were covered for $20 such that cost by car was $12 which is 60% of total expense. So x = 60.
Distance covered by car was 1 km out of 2 km so 50% of the total distance. So y = 50.

In the options, put x = 60 and look for the option that gives 50.
Only option (B) does.

In GMAT questions, 'none of these' is not an option so there wouldn't be any problem.
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A man needs to travel a certain distance. He travels certain distance by car and the rest by train. Car travel costs him $12 per km and travelling by train costs him $8 per km. If the total amount spent on car travel was x% of the total amount spent on whole journey and the total distance traveled by car was y% of the total distance covered, what is the value of y in terms of x?

A. x/(100-x)

B. 200x/(300-x)

C. 300x/(200-x)

D. 200x/(x-300)

E. None of these

Alternatively, assuming total distance travelled as 100, y will be travelled by car and (100 - y) by train. So total cost by car will be 12y and that by train will be 8(100 - y)

\(\frac{x}{100} = \frac{12y}{12y + 8(100 - y)}\)

\(\frac{100}{x} = \frac{12y + 8(100 - y)}{12y}\)

\(\frac{1200}{x} = \frac{4y + 800}{y}\)

\(\frac{1200-4x}{x} = \frac{800}{y}\)

\(y = \frac{200x}{300-x}\)

Answer (B)
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Here's my approach.

Car's Cost: x%
Train's Cost: 1-x%

Car's Distance: y%
y% = Car's Distance/Total distance x 100%

Total distance: x%/12 + (1-x%)/8
Car's Distance : x%/12

Put them together: y % = (x%/12)/ [x%/12 + (1-x%)/8]
Simplify: y%= 2x/(300-x),
Finalize: y = 200x/(300-x)
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Deconstructing the Question
Car Cost = $12/km.
Train Cost = $8/km.
Given:
1. Car Cost is \(x\%\) of Total Cost.
2. Car Distance is \(y\%\) of Total Distance.
Target: Find \(y\) in terms of \(x\).

Step 1: Set up Variables (or Smart Numbers)
Let Total Distance = 100 units (to make percentages easy).
Then:
- Distance by Car = \(y\)
- Distance by Train = \(100 - y\)

Step 2: Calculate Costs
- Cost by Car (\(C_c\)) = \(12 \times y = 12y\)
- Cost by Train (\(C_t\)) = \(8 \times (100 - y) = 800 - 8y\)
- Total Cost (\(C_{tot}\)) = \(12y + 800 - 8y = 4y + 800\)

Step 3: Relate to x
We are given that \(C_c\) is \(x\%\) of \(C_{tot}\).
Equation:
\(\frac{C_c}{C_{tot}} = \frac{x}{100}\)
\(\frac{12y}{4y + 800} = \frac{x}{100}\)

Simplify the left side by dividing numerator and denominator by 4:
\(\frac{3y}{y + 200} = \frac{x}{100}\)

Step 4: Solve for y
Cross-multiply:
\(300y = x(y + 200)\)
\(300y = xy + 200x\)

Rearrange to isolate \(y\):
\(300y - xy = 200x\)
\(y(300 - x) = 200x\)
\(y = \frac{200x}{300 - x}\)

Answer: B
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Step 1: Set up what we know
- Car travel: $12 per km
- Train travel: $8 per km
- Car cost = x% of total cost
- Car distance = y% of total distance (we need to find this)

Step 2: Use percentages to write equations
If car distance is y% of total distance:
- Car distance = (y/100) × Total Distance
- Train distance = ((100-y)/100) × Total Distance

Step 3: Write the cost equation
Car cost = x% of total cost means:
12 × Car distance = (x/100) × (Car cost + Train cost)

Substituting:
12 × (y/100) × D = (x/100) × [12 × (y/100) × D + 8 × ((100-y)/100) × D]

Step 4: Simplify (divide by D and multiply by 100)
12y = x × [12y/100 + 8(100-y)/100]
12y = x × [(12y + 800 - 8y)/100]
12y = x × [(4y + 800)/100]
1200y = x(4y + 800)
1200y = 4xy + 800x
1200y - 4xy = 800x
y(1200 - 4x) = 800x

Therefore:
y = 800x/(1200 - 4x) = 800x/[4(300 - x)] = 200x/(300 - x)

Answer: B. 200x/(300-x)

GM10
Bunuel VeritasKarishma can you please help with the above question?

Thanks
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