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RonPurewal
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RonPurewal
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A drugstore chain can return empty lipsticks that it originally sold to the supplier for recycling. To encourage customers to return their empty lipsticks to its stores rather than throw them in the trash, the drugstore chain has instituted a new policy allowing customers to bring empty lipsticks to a store and exchange them for a new, full lipstick, as shown in the diagram.

Select from each drop-down menu the option that creates the most accurate statement based on the information provided.

Dara has 11 empty lipsticks originally purchased from this drugstore chain. If Dara exchanges these for new lipsticks under the store policy, wears the new lipsticks until they run out, and then repeats these actions (with the lipsticks that are now empty) to the fullest extent possible—without acquiring any additional lipsticks outside of the exchange program—then Dara will be able to acquire and wear new lipsticks, and will have upon reaching “End”.
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nice question , she will have a total of 5 lipsticks to use for after replacing 11 lipsticks in seq (9 empty lipsticks will yield 3 lipsticks & 2 empty lipsticks and 1 full lipsticks used which along with other 2 lipsticks will be replaced to add 1 full so now we have 3 full again which once used fully will yield 1 full and this again used full will not yield any more this the cycle ends) and 1 empty lipstick at the end
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Nice flowchart question — this is pure process simulation, which is the core skill in Graphs and Tables questions involving decision-tree diagrams. The walkthrough above is correct, but let me explain the conceptual approach that makes these go faster on test day.

The key concept: When you see a flowchart with a loop (an arrow that cycles back to a decision box), treat it like a "while loop" — keep iterating until the exit condition is met.

The exchange rule from the diagram:
- Have 3 or more empty lipsticks? → Yes → Exchange 3 empties for 1 new full → use it → loop back
- Have 1 or more full lipstick? → Yes → Use it until empty → loop back
- Neither condition met → End

The common trap: Students count only "how many new lipsticks she exchanged for" but forget that each new lipstick she uses also becomes an empty that re-enters the loop. You have to track both counts simultaneously: empties in hand AND new lipsticks acquired.

Simulation with 11 empties:

Round 1: 11 empties → 11 ÷ 3 = 3 exchanges (remainder 2) → get 3 new lipsticks, use all 3 → now have 2 (leftover) + 3 (from used ones) = 5 empties. New acquired: 3.

Round 2: 5 empties → 5 ÷ 3 = 1 exchange (remainder 2) → get 1 new lipstick, use it → now have 2 + 1 = 3 empties. New acquired: 1.

Round 3: 3 empties → 3 ÷ 3 = 1 exchange (remainder 0) → get 1 new lipstick, use it → now have 0 + 1 = 1 empty. New acquired: 1.

End: 1 empty left. Less than 3 empties and no full lipsticks → exit the loop.

Total new lipsticks acquired and worn: 3 + 1 + 1 = 5
Empties remaining at "End": 1

Answer: 5 new lipsticks, 1 empty lipstick remaining.

The time-saving trick is handling Round 1 as a batch — 11 ÷ 3 = 3 remainder 2 — rather than going one exchange at a time (which some people do and lose 30-45 seconds). Group the exchanges within each iteration, then move to the next round.

(Kavya | 725 on GMAT Focus Edition)
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Nice solutions Dereno, MS26, and Edskore.


Edskore
The key concept: When you see a flowchart with a loop (an arrow that cycles back to a decision box), treat it like a "while loop" —
Well, only if you actually have coding experience ahahhah. For those of us who don't code, this would be a whole pile of new stuff to learn on top of what's actually in the problems.
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