Six computers, each working at the same constant rate, together can

Question

Six computers, each working at the same constant rate, together can process a certain amount of data in 15 days. How many additional computers, each working at the same constant rate, will be needed to process the same amount of data in 10 days?

(A) 3
(B) 5
(C) 6
(D) 9
(E) 12

(A) 3
(B) 5
(C) 6
(D) 9
(E) 12

KarishmaB · Accepted Answer

Number of computers and days taken have an inverse relation. i.e. if number of computers increase, days taken will reduce... Agreed?

If to complete the work in 15 days, you need 6 computers,
then to complete the work in 1 day, how many computers will you need?
You will need more computers now so you multiply 15 by 6 i.e. 15*6 = 90 computers.

To complete the work in 1 day, you need 90 computers.
To complete the work in 10 days, how many computers will you need? You will need fewer computers now, right? So you divide 90 by 10 to get 90/10 = 9 computers. You need 3 extra computers.

Another way: 
15 days .................. 6 computers
10 days ...................? computers
Unknown is the number of computers. You need to change the previous number of computers to get the new number. You will need to multiply either by 15/10 or 10/15. If you have fewer number of days, you will need more computers so you multiply by 15/10 (i.e. greater than 1) to give a bigger number
6*(15/10) = 9

Another way:
Days (d) and computers (c) are inversely proportional.
dc = k (a constant)
Say x is the new number of computers.
15*6 = k
10*x = k
15*6 = 10*x
x = 9

Finally, the given explanation way:
6 computers need 15 days. This means each computer is working for 15 days. How much total work is there? Work which needs 6 computers working simultaneously for 15 days so 15+15+15+15+15+15 = 90 days will be needed if only 1 computer were working.
Now, if we need to finish the total work in 10 days, how many computers do we need? 10 + 10 + 10 ..... = 90
We will need 9 such computers to finish the given work.

n2739178 · Answer

4. A
Explanation: If six computers require 15 days to process the data, thats
a total of 90 computer-days the product of 6 and 15. If you change the number
of computers or the number of days, 90 will have to remain the product, whether
that means 90 days of one computer or one day with 90 computers.
In 10 days, the number of computers is:
10c = 90
c = 9
9 computers is 3 more than the 6 that it took to do the job in 15 days, so
the correct choice is (A).

...WHAT I DON'T GET, is this business about "90 computer days"... is there another way to solve it? I wouldn't have known at all to solve it the way they solved it

MHIKER · Answer

To complete in 15 days 6 computers required
so '' 10 = 6*15/10 = 9
so additional 3 computers required.
Ans A.

Abhishek009 · Answer

Total work = Computer * Days 
Total work = 15 * 6 => 90

Total work = Computer * Days

90 = Computer * 10

So, Total computers required is 9

So, additional computers required is 3 ( 9 - 6 )

So, Correct answer will be (A)

fantaisie · Answer

6 computers do work in 15 days, or they do  \frac{1}{15}  of the job per day together
Thus one computer does  \frac{1}{15} * \frac{1}{6}  =  \frac{1}{90}  per day

How many computers would we need in total to complete the job in 10 days?

1/  \frac{1}{90}  * X = 10 days
 \frac{90}{X}  = 10 days
90 = 10X
X = 9

In total we need 9 computers to complete the work. Since we already have 6, we need extra 3.

CounterSniper · Answer

let the total work be 1

now,
1 work is done in 6*15 computer days = 90 computer days
same work has to be done in x*10 computer days.
Therefore,

6*15=x*10
x=9

additional computers = 3

Henry S. Hudson Jr. · Answer

Once you see enough of these problems you realize perhaps the most efficient way to solve them is to set up a simple multiplication equation.

6(15)=10(x) .

90=10x

9=x.

Be careful, to answer the question we must attend to additional hours. The answer is  9-6=3 .

This issue could be bypassed by setting up this equation.  6(15)=(6+x)(10)

Dividing both sides by 2(5) we obtain  9=6+x

Hence, x=3

EgmatQuantExpert · Answer

Solution

Given
  
 • Six computers, each works at the same constant rate.
• Together, all 6 computers can process a certain amount of data in 15 days.

To find
 • The number of additional computers required process the same amount of data in 10 days if all of them works at the same constant rate.

Approach

Let us assume the amount of work done by 1 computer in 1 day = C units
 • 6 computers can do= 6C units in 1 day.
• In 15 days, 6 computers can do= 6C * 15 units.

Hence, total units of data to be processed = 90 C.
Let’s say x additional computers are required and all of the computers combined need to complete the work in 10 days.
 • So, work done all the computers combined = (6 + x) * 10 * C= (6+x) * 10 C
• This work should be equal to 90C.
• Hence, (6+x) * 10 C = 90 C
 o x = 3 
 
Hence, the correct answer is option A.

Archit3110 · Answer

when rate given is same
m1*t1/w1=m2*t2/w2
here work required to be done is same so w1=w1
6*15/w1=x*10/w1
x=9 
so total 9-6; 3 additional required
IMO A

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Six computers, each working at the same constant rate, together can

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