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27 Mar 2015, 06:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
74% (02:56) correct
26%
(03:04)
wrong
based on 634
sessions
History
Date
Time
Result
Not Attempted Yet
Jan’s house and Cindy’s house are joined by a straight road 24 miles long. Jan and Cindy agree to meet at a restaurant along that road, twice as far from Jan’s house as from Cindy’s. Beginning at noon, Cindy walks to the restaurant at a constant speed of 3 miles per hour. Later, Jan drives to the restaurant at a constant speed of 30 miles per hour. If they arrive at the restaurant simultaneously, at what time did Jan begin her drive?
A) 12:32
B) 1:25
C) 1:52
D) 2:08
E) 2:40
A) 12:32
B) 1:25
C) 1:52
D) 2:08
E) 2:40
27 Mar 2015, 06:21
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Since restaurant is twice as far from Jan’s house as from Cindy’s. It should be 16 miles from Jan's house and 8 miles from Cindy's.
Cindy will take 8/3 hours = 2 hours and 40 minutes to reach the restaurant.
Jan will take 16/30 hours = 32 minutes to reach the restaurant.
Hence, they Jan needs to start at 2:08 so that both reach the restaurant at same time.
Cindy will take 8/3 hours = 2 hours and 40 minutes to reach the restaurant.
Jan will take 16/30 hours = 32 minutes to reach the restaurant.
Hence, they Jan needs to start at 2:08 so that both reach the restaurant at same time.
02 Apr 2015, 00:09
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Answer = D = 2:08
Refer diagram below:
rest.png [ 4.19 KiB | Viewed 8385 times ]
Time required by Cindy \(= 60*\frac{8}{3} = 160\) minutes
Cindy reached at 14:40 to the restaurant
Time required by Jan \(= 60*\frac{16}{30} = 32\) minutes
Jan started at 14:40-0:32 = 14:08
Refer diagram below:
Attachment:
rest.png [ 4.19 KiB | Viewed 8385 times ]
Time required by Cindy \(= 60*\frac{8}{3} = 160\) minutes
Cindy reached at 14:40 to the restaurant
Time required by Jan \(= 60*\frac{16}{30} = 32\) minutes
Jan started at 14:40-0:32 = 14:08
