Last visit was: 24 Apr 2026, 08:58 It is currently 24 Apr 2026, 08:58
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,814
Own Kudos:
Given Kudos: 105,871
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,814
Kudos: 811,028
 [28]
1
Kudos
Add Kudos
27
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
TeamGMATIFY
Joined: 20 Aug 2015
Last visit: 31 Oct 2016
Posts: 339
Own Kudos:
1,527
 [15]
Given Kudos: 10
Location: India
GMAT 1: 760 Q50 V44
Expert
Expert reply
GMAT 1: 760 Q50 V44
Posts: 339
Kudos: 1,527
 [15]
5
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
User avatar
sowragu
Joined: 25 Dec 2012
Last visit: 26 Apr 2016
Posts: 103
Own Kudos:
128
 [2]
Given Kudos: 148
Posts: 103
Kudos: 128
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
General Discussion
User avatar
stonecold
Joined: 12 Aug 2015
Last visit: 09 Apr 2024
Posts: 2,231
Own Kudos:
Given Kudos: 893
GRE 1: Q169 V154
GRE 1: Q169 V154
Posts: 2,231
Kudos: 3,643
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Here D = B^2-AC = 28
so the roots are 2√5 +√28/2 and 2√5 -28/2
hence M^2 +N^2 => 28
i.e. D
User avatar
rhine29388
Joined: 24 Nov 2015
Last visit: 21 Oct 2019
Posts: 386
Own Kudos:
Given Kudos: 231
Location: United States (LA)
Products:
Posts: 386
Kudos: 146
Kudos
Add Kudos
Bookmarks
Bookmark this Post
stonecold
Here D = B^2-AC = 28
so the roots are 2√5 +√28/2 and 2√5 -28/2
hence M^2 +N^2 => 28
i.e. D
Apology for seeing a typo error It should be 24 and not 28.
User avatar
adiagr
Joined: 18 Jan 2010
Last visit: 05 Oct 2019
Posts: 202
Own Kudos:
1,155
 [1]
Given Kudos: 9
GMAT 1: 710 Q48 V40
Posts: 202
Kudos: 1,155
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
If m and n are the roots of the quadratic equation \(x^2 - (2 \sqrt 5)x - 2 = 0\), the value of \(m^2 + n^2\) is:

A. 18
B. 20
C. 22
D. 24
E. 32

m+n = -{- (2 \sqrt 5)}
mn = -2

Squaring 1st equation we get

\(m^2+n^2+2mn = 20\)

\(m^2+n^2= 20 - 2 *(-2)\)

\(m^2+n^2= 20 + 4\) = 24

D is the answer.
User avatar
jfranciscocuencag
Joined: 12 Sep 2017
Last visit: 17 Aug 2024
Posts: 227
Own Kudos:
144
 [1]
Given Kudos: 132
Posts: 227
Kudos: 144
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
TeamGMATIFY
Bunuel
If m and n are the roots of the quadratic equation \(x^2 - (2 \sqrt 5)x - 2 = 0\), the value of \(m^2 + n^2\) is:

A. 18
B. 20
C. 22
D. 24
E. 32

In the equation ax^2 + bx + c =0
Sum of roots = -b/a
Product of roots = c/a


Sum of roots (m + n) = \((2 \sqrt 5)\)
Product of roots (mn) = -2

\(m^2 + n^2\) = \((m + n)^2 - 2mn\) = 20 + 4 = 24
Option D

Hello!

Could someone please clarify to me why \(m^2 + n^2\) is the same as:

\(m^2 - 2mn + n^2\)

Kind regards!
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 24 Apr 2026
Posts: 22,283
Own Kudos:
26,534
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,283
Kudos: 26,534
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
If m and n are the roots of the quadratic equation \(x^2 - (2 \sqrt 5)x - 2 = 0\), the value of \(m^2 + n^2\) is:

A. 18
B. 20
C. 22
D. 24
E. 32

For any quadratic equation of the form x^2 + bx + c = 0, if r and s are the roots of the equation, then r + s = -b and rs = c. So here we have:

m + n = 2√5 and mn = -2

Squaring the first equation, we have:

(m + n)^2 = (2√5)^2

m^2 + 2mn + n^2 = 20

Since mn = -2, we have:

m^2 + 2(-2) + n^2 = 20

m^2 - 4 + n^2 = 20

m^2 + n^2 = 24

Answer: D
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,974
Own Kudos:
Posts: 38,974
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109814 posts
Tuck School Moderator
853 posts