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Speed of A= \(\frac{375}{5}\)= 75 miles/hr
Speed of B= \(\frac{2}{3}\) of 75= 50 miles/hr

Both of them are moving in opposite direction.

Relative Speed= (75+50)= 125 miles/hr

Time taken to cover the entire distance= \(\frac{375}{125}\)= 3 hrs
Distance covered by A in 3 hrs= 75*3= 225 miles.

Answer: C.

Kudos please if you like my explanation!
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Bunuel
Two motorists start a journey at opposite ends of the state and travel the same road toward one another. Motorist A travels the 375 miles across the state in 5 hours, while Motorist B travels at an average rate one-third slower than Motorist B travels. If each motorist finishes where the other started and both drove continuously until each of the respective trips was completed, how far had Motorist A driven, in miles, when his car passed that of Motorist B?

A. 275
B. 250
C. 225
D. 215
E. 210

We can use the following formula:

distance of A + distance of B = total distance = 375

We are given that the rate of Motorist A is 375/5 = 75 mph and that the rate of Motorist B is 1/3 slower, or 2/3(75) = 50 mph. We can let the time of each motorist = t. Thus:

75t + 50t = 375

125t = 375

t = 3

Thus, Motorist A had driven 75 x 3 = 225 miles when he passed Motorist B’s car.

Answer: C
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speed of A ; 375/5 ; 75 mph
speed of B ; 75*2/3 ; 50 mph
total relative speed ; 125 mph
time ; 375/125 ; 3hrs
so Distance of A when it overtakes B ; 3*75 ; 225
IMO C


Bunuel
Two motorists start a journey at opposite ends of the state and travel the same road toward one another. Motorist A travels the 375 miles across the state in 5 hours, while Motorist B travels at an average rate one-third slower than Motorist A travels. If each motorist finishes where the other started and both drove continuously until each of the respective trips was completed, how far had Motorist A driven, in miles, when his car passed that of Motorist B?

A. 275
B. 250
C. 225
D. 215
E. 210
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Bunuel
Two motorists start a journey at opposite ends of the state and travel the same road toward one another. Motorist A travels the 375 miles across the state in 5 hours, while Motorist B travels at an average rate one-third slower than Motorist A travels. If each motorist finishes where the other started and both drove continuously until each of the respective trips was completed, how far had Motorist A driven, in miles, when his car passed that of Motorist B?

A. 275
B. 250
C. 225
D. 215
E. 210

The two speeds have a direct proportion, the ratio of A's speed to B's is \(1 : \frac{2}{3}\) or \(3:2\). Since they both travel the same amount of time, their distance covered must also have a ratio of \(3:2\). We also know the total distance is 375 miles. Then they will split the 375 miles into 5 equivalent portions, 3 portions belong to A and 2 other portions belong to B. Hence 3/5's of the total distance is traveled by A and the rest by B. \(375 * \frac{3}{5} = 225\).

Ans: C

Once the student masters this ratio method, the only calculation required is 3+2 = 5 then \(375 * \frac{3}{5} = 225\).
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Bunuel
Two motorists start a journey at opposite ends of the state and travel the same road toward one another. Motorist A travels the 375 miles across the state in 5 hours, while Motorist B travels at an average rate one-third slower than Motorist A travels. If each motorist finishes where the other started and both drove continuously until each of the respective trips was completed, how far had Motorist A driven, in miles, when his car passed that of Motorist B?

A. 275
B. 250
C. 225
D. 215
E. 210

Given:
1. Two motorists start a journey at opposite ends of the state and travel the same road toward one another.
2. Motorist A travels the 375 miles across the state in 5 hours, while Motorist B travels at an average rate one-third slower than Motorist A travels.

Asked: If each motorist finishes where the other started and both drove continuously until each of the respective trips was completed, how far had Motorist A driven, in miles, when his car passed that of Motorist B?

Speed of motorist A = 375/5 = 75 mph
Speed of motorist B = 2/3 * 75 = 50 mph

Time taken to meet = 375/(50+75) = 375/125 = 3 hours

Distance travelled by A in 3 hours = 3 * 75 = 225 miles

IMO C
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