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Bunuel

In square PQRS above, QR = 1, RU = US, and PT = TS. What is the area of the quadrilateral PRUT?

(A) 1/8
(B) 1/4
(C) 3/8
(D) 5/8
(E) 2/3


Attachment:
2017-10-11_1127.png

The area of square QRPS is 1 x 1 = 1.

The area of triangle QRP is 1/2.

The area of triangle TUS is 1/2 x 1/2 x 1/2 = 1/8.

Thus, the area of the quadrilateral PRUT is 1 - (1/2 + 1/8) = 1 - (4/8 + 1/8) = 3/8.

Answer: C
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Area of PRUT = Area of PQRS - Area of UST - Area of PQR

Area of PQRS = 1*1 = 1

Since QR = PQ = 1 so Area of PQR = 1/2 * 1 * 1 = 1/2

Since RU = US = ST = PT = 1/2 so Area of UST = 1/2 * 1/2 * 1/2 = 1/8

So the area of PRUT = 1 -1/2 -1/8 = 3/8

ANSWER: C
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Bunuel

In square PQRS above, QR = 1, RU = US, and PT = TS. What is the area of the quadrilateral PRUT?

(A) 1/8
(B) 1/4
(C) 3/8
(D) 5/8
(E) 2/3


Attachment:
2017-10-11_1127.png

If we divide square into triangles it would be 8 triangles of equal area
in shaded portion there are 3 triangles so ea of Quad is 3/8
Answer is C
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Bunuel

In square PQRS above, QR = 1, RU = US, and PT = TS. What is the area of the quadrilateral PRUT?

(A) 1/8
(B) 1/4
(C) 3/8
(D) 5/8
(E) 2/3

Attachment:
2017-10-11_1127.png
\((Area_{square}) - (Area_{2triangles}) = (Area_{quad})\)

Square side length = 1
Top triangle legs' length = 1
Bottom triangle legs' length* = \(\frac{1}{2}\)

Area of square: \(s^2 = 1^2 = 1\)
Area of top triangle: \(\frac{s^2}{2}=\frac{1}{2}\)
Area of bottom triangle: \(\frac{s^2}{2} \\
=\frac{(\frac{1}{4})}{2} = \frac{1}{8}\)

Both triangles' area:
\(\frac{1}{2} + \frac{1}{8} = \frac{5}{8}\)

Quadrilateral area: \(1 - \frac{5}{8}=\frac{3}{8}\)

Answer C

*The segments that constitute the legs of this right triangle are both \(\frac{1}{2}\) the length of the side of the square because they are half of a bisected side.
Square side RS is bisected; we are given that RU = US. Square side PS is similarly bisected.
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