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Bunuel
If a baker made 60 pies in the first 5 hours of his workday, by how many pies per hour did he increase his rate in the last 3 hours of the workday in order to complete 150 pies in the entire 8- hour period?

(A) 12
(B) 14
(C) 16
(D) 18
(E) 20


Phase 1 :

60 pies were made in 5 hrs

so, 60/5 = 12 pies / hr.

Phase 2:

work left = 90 pies
Time left = 3 hrs.

so, rate = 90 /3 = 30 pies / hr.


Difference = 30 - 12 = 18.

In last 3 hrs Baker produced extra 18 pies / hr.

Thus the best answer is D.
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Bunuel
If a baker made 60 pies in the first 5 hours of his workday, by how many pies per hour did he increase his rate in the last 3 hours of the workday in order to complete 150 pies in the entire 8- hour period?

(A) 12
(B) 14
(C) 16
(D) 18
(E) 20
The efficiency of the baker is 12 pies/hour

In first 5 hours the baker bakes 60 pies, so in the next 3 hours he will have to bake 90 pies...

So, Efficiency during the last 3 hours is 30 pies / hour

Hence, during the last three hours, he increased by efficiency by 18 pies/hour ( 30 - 23), Answer must be (D)
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Baker made 60 pies in the first 5 hours of his workday: In 1 hour he makes \(\frac{60 }{ 5}\) = 12 pies.

Total hours: 8
Total Pies: 150

Remaining hours: 8 - 5 = 3
Remaining pies: 150 - 60 = 90

Remaining pies per hour: \(\frac{90 }{ 3}\) = 30

Difference in per hour pies: 30 - 12 = 18

Answer D
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Given

• A baker made 60 pies in the first 5 hours of his workday.

To Find

    • By how many pies per hour did he increase his rate in the last 3 hours of the workday in order to complete 150 pies in the entire 8- hour period.

Approach and Working Out


    • Current speed = \(\frac{60}{5}\) = 12 pieces/ hour.
    • Remaining pieces = 150 – 60 = 90
      o Speed required = \(\frac{90}{3}\) = 30 per hour
    • Increase = 30 – 12 = 18


Correct Answer: Option D
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