How many integers between 101 and 201 are equal to the square of some

Question

How many integers between 101 and 201 are equal to the square of some integer ?

A. Two
B. There
C. Four
D. Five
E. Six

kunalcvrce · Answer

Four integers  11^2,12^2,13^2,14^2 
C

Archit3110 · Answer

101 to 201 
square integers =
121,144,169,196
IMO C

Hoozan · Answer

Just wanted to know... Of eight was in the option what would be the answer?

Because the square of a negative number would also give us the same value.

Eg- 11^2 = -11^2

Thus there would be 8 integer values that would give us values between 101 and 201

Posted from my mobile device

Archit3110 · Answer

Hoozan 
rang given is 101 to 201 ; which is +ve ;

Hoozan · Answer

How many integers between 101 and 201 are equal to the square of some integer ?

Set = (101,102..200)

Now we are asked to find integers that are square of some integer

Thus we can narrow the set to 
121,144,169 and 196

Thus the question is asking us to find the integers whose square value is in the above set

I.e... 11^=-11^= 121

The question has given us a range of n^2 and not of n

Which means n could be +ve or -ve.

Posted from my mobile device

Archit3110 · Answer

Hoozan

My understanding of question is:

question has asked for " see bold"

How many integers between 101 and 201  are equal to the square of some integer ?

so those integers values are only 4 , even if the square is either -ve or +ve.. 
question isnt asking for the no of integers who have a square between 101 to 201... in that case 8 would be correct..

Hoozan · Answer

How many integers between 101 and 201 are equal to the "square of some integer"

Notice the word Square of SOME INTEGER

my understanding is N^2 lies in the given range and we need to find the number of values that satisfies

101<=N^2<=201

Posted from my mobile device

KarishmaB · Answer

Look for the closest perfect square less than 101. It is 100 (which is 10^2).
The greatest perfect square more than 201 is 225 (15^2)

So 11^2 = 121, 12^2 = 144, 13^2 = 169 and 14^2 = 196 lie in the given range.

Hence, 121, 144, 169 and 196 are the four integers between 101 and 201 which are square of some integers. 
Note that 121 is the square of two integers (11 and -11). Still, it will be counted once only because both squared give 121 only. Even if 121 is the square of 2 different numbers, still it can be counted only once.

Answer (C)

Hoozan · Answer

So if the answer choice had eight we would still go with 4?

Because though 11 and -11 give 1 value i.e 121 we have 2 different integers which give us 121

Posted from my mobile device

ScottTargetTestPrep · Answer

The perfect squares between 101 and 201 are 121, 144, 169, and 196, which are 11^2, 12^2, 13^2, and 14^2, respectively.

Answer: C

KSBGC · Answer

between 101 and 201

121 = 11^2

196 = 14^2

11 , 12 , 13 , 14.

4 integers.

C is the correct answer.

bumpbot · Answer

Automated notice from GMAT Club BumpBot: 

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

 This post was generated automatically.

How many integers between 101 and 201 are equal to the square of some

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Problem Solving (PS) Questions

How many integers between 101 and 201 are equal to the square of some

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards