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25 Feb 2019, 02:46
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (01:25) correct
13%
(01:51)
wrong
based on 46
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure above, if BD is perpendicular to AC and AC = 21, then AD =
A. 12
B. 13
C. 20
D. 21
E. 25
Attachment:
2019-02-25_1345.png [ 18.14 KiB | Viewed 2066 times ]
25 Feb 2019, 03:01
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Bunuel
\(BD^2 = 13^2 - 5^2\)
\(BD^2 = 144\)
BD = 12.
Given ,
AC = 21
BC = 5
AB = 16.
\(AD^2 = BD^2 + AB^2\)
\(AD^2 = 12^2 + 16^2\)
\(AD^2 = 144 + 256\)
\(AD^2 = 400\)
AD = 20.
C is the correct answer.
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25 Feb 2019, 20:39
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Triangle BCD is a right angle triangle
thus \(BD^2\)=\(CD^2\)-\(BC^2\)
hence \(13^2\)-\(5^2\) =144
BD=12
now considering other right angle triangle ABD
\(BD^2+ AB^2 = AD^2\)
\(12^2 +(21-5)^2 = 12^2+16^2 = 400\)
thus AD =20
Answer C
thus \(BD^2\)=\(CD^2\)-\(BC^2\)
hence \(13^2\)-\(5^2\) =144
BD=12
now considering other right angle triangle ABD
\(BD^2+ AB^2 = AD^2\)
\(12^2 +(21-5)^2 = 12^2+16^2 = 400\)
thus AD =20
Answer C
