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length of Ladder, AC= x
Length of wall, CE= x

CB=x-2

Triangle ABC is a right angle triangle

Hence, \(AB^2+BC^2=AC^2\) {pythagoras theorem}

\(10^2+(x-2)^2=x^2\)

x= 26 ft
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The length of a ladder is exactly equal to the height of the wall. If a ladder is placed on a 2 ft stool, placed 10 ft away from the wall, then the top of the ladder just reaches the top of the wall.Find the height of the wall.

(A) 25
(B) 26
(C) 27
(D) 28
(E) 29

Let 'x' be the height of ladder and wall. As described in question the ladder and wall would form a trapezium with parallel sides of length 'x' and '2' and non-parallel sides of length '10' and 'x'. Refer diagram below.

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In right angled triangle ADE, x^2 = 10^2 + (x - 2)^2

Solving the equation gives x = 26

Answer B.
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from given info
we can say
height of ladder =x
x^2= (x-2)^2+10^2
solve for x = 24 + 2 ; 26
IMO B

The length of a ladder is exactly equal to the height of the wall. If a ladder is placed on a 2 ft stool, placed 10 ft away from the wall, then the top of the ladder just reaches the top of the wall.Find the height of the wall.

(A) 25
(B) 26
(C) 27
(D) 28
(E) 29
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Let:
height of the wall = h;
length of ladder= l

Given, h=l
Since ladder is placed on top of the stool, the relative height till it touches the wall= (h-2)ft
Since the ladder is placed 10ft away from the wall, the horizontal distance= 10ft

Applying Pythagoras Theorem, (h-2)^2 + 10^2 = h^2
Thus, h^2 - 4h +4 + 100 = h^2
Thus, h= 104/4
Thus, h= 26 ______ [Option B ]
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Quote:
The length of a ladder is exactly equal to the height of the wall. If a ladder is placed on a 2 ft stool, placed 10 ft away from the wall, then the top of the ladder just reaches the top of the wall.Find the height of the wall.

(A) 25
(B) 26
(C) 27
(D) 28
(E) 29

imagine a triangle:
hypotenuse x (ladder)
base 10 (floor)
height x-2 (wall minus the stool)

\(x^2=(x-2)^2+10^2…x^2=x^2+4-4x+100…4(x-1)=100…x=25+1=26\)

Answer (B)
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height of wall=height of ladder, h
We are given that the ladder is placed on a stool which is 2ft tall, and the stool is 10ft away from the wall. The height of the wall referenced to the stool is now (h-2).
We are to determine the height of the wall, h.

From the calculations in the figure below, h=26ft


The answer is therefore B.

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The length of the ladder = the length of the wall. —let x be the length of them

—> if ladder is placed on a 2 ft long stool, placed 10 ft away from the wall and leaned against the wall, then the top of ladder reaches the top of the wall.
—> the right—angled triangle can be drawn
—> \(x^{2}\)= \(10^{2}+ (x—2)^{2}\)

\(x^{2}= 100+ x^{2}—4*x+ 4\)
4*x= 104
x =26

The answer is B

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x is the height of the wall
x is the length of the ladder
10 is the distance of the ground between the wall and the ladder

(x-2)^2+10^2=x^2
x^2-4x-4+100=x^2
4x-4=100
4x=104
x=26

Therefore, B
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