A starts from X at 9:00 am and reaches Y at 1:00 pm. B starts from Y

Question

A starts from X at 9:00 am and reaches Y at 1:00 pm. B starts from Y at 9:00 am and reaches X at 3 pm. At what time do the two meet?

A. 11:20 am.
B. 11:22 am.
C. 11:24 am.
D. 11:26 am.
E. 11:28 am.

Archit3110 · Answer

let d= 4 km
so A speed ; 4/4 ; 1kmph
and B speed ; 4/6 ; 2/3 kmph
since in opposite directions so speed = 1+2/3 ; 5/3 kmph
so time ; 4*3/5 ; 2.4 hrs or say 2 hrs and 24 mins from 9 am ; IMO C 11:24 am

gurmukh · Answer

Let total distance =12 km 
A's speed = 3km/hr 
B's speed = 2 km//hr
Combined speed = 5km/hr 
Time taken together =12/5
 =2.4 hrs
They will meet at 11:24 am
Option C is the answer

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fireagablast · Answer

9am-1pm = 4hr
9am-3pm = 6hr

d/(d/4+d/6) = 1/(1/4+1/6) = 24/10 = 2.4 = 2hr 2/5hr = 2hr 24min --->9+2:24 = 11:24am

gurmukh · Answer

Let the total distance is d and the time taken to meet t
d/4×t + d/6×t = d
1/4×t + 1/6×t = 1
 T = 2.4 hrs

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CrackverbalGMAT · Answer

This question sounds more like a Time & work question, especially if you solve it like the way I wish to solve it.

The distance between X and Y is constant. A takes 4 hours to cover this distance whereas B takes 6 hours to cover the same distance.

This way, we can assume the distance between X and Y as the LCM of 4 and 6 i.e. 12 miles. Therefore, 
Speed of A =  \frac{12 }{ 4}  = 3 miles per hour and Speed of B =  \frac{12 }{ 6}  = 2 miles per hour.

Since they start at the same time, Relative Speed = 5 miles per hour.

Time taken to meet =  \frac{Distance between A and B }{ Relative Speed
}

i.e. Time =  \frac{12 }{ 5}  hours =  \frac{12 }{ 5}  * 60 = 144 minutes = 2 hours 24 minutes from 9 AM which is nothing but 11:24 AM.

The correct answer option is C .

Hope that helps!

ScottTargetTestPrep · Answer

The rate for A is D/4, and the rate for B is D/6, and they both travel for T hours. Thus:

DT/4 + DT/6 = D

D(T/4 + T/6) = D

T/4 + T/6 = 1

Multiplying by 12, we have:

3T + 2T = 12

5T = 12

T = 12/5 = 2.4 hours = 2 hours 24 minutes. So, A and B met at 9 am + 2 hour 24 minutes = 11:24 am.

Answer: C

lavanya.18 · Answer

Total time by A: 4hrs
Total time by B: 6 hrs
Let total distance be LCM of 4 and 6 ie 12
So speed of A= 12/4 = 3
Speed of B= 12/6 = 2

Time of meeting= distance/ Speed of A+ Speed of B = 12/ 3+2 = 12/5 = 2.4 hours
2.4 hrs is 11:24- TIME OF MEETING

Therefore, the answer is C

A starts from X at 9:00 am and reaches Y at 1:00 pm. B starts from Y

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GMAT Problem Solving (PS) Questions

A starts from X at 9:00 am and reaches Y at 1:00 pm. B starts from Y

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