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MathRevolution
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Since \(ab < 0, a\) and \(b\) have different signs.

Since \(a – b > 0\), we have \(a > b.\)

Since \(a\) and \(b\) have different signs with \(a > b, a\) is positive, and \(b\) is negative.

Then \(|a| + |b| = a + (-b) = a – b.\)

Therefore, B is the correct answer.
Answer: B
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=>

Since \(ab < 0, a\) and \(b\) have different signs.

Since \(a – b > 0\), we have \(a > b.\)

Since \(a\) and \(b\) have different signs with \(a > b, a\) is positive, and \(b\) is negative.

Then \(|a| + |b| = a + (-b) = a – b.\)

Therefore, B is the correct answer.
Answer: B

Hello,

\(b<0\), but since \(b\) is inside the modulus so the the value will \(b\), right ? not \(-b\).
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How do did you arrive at a-b when b is inside the modulus? Sorry, I am getting confused on this step.
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Yes2GMAT
MathRevolution

How do did you arrive at a-b when b is inside the modulus? Sorry, I am getting confused on this step.

I think the easier way to solve this question and understand it would be picking numbers. I would recommend that you pick numbers and then he’ll be clear.

Tip - because the absolute value makes the number positive, and B is negative, to turn B into positive you need a negative sign in front of that negative number. Again I think it will be easier to understand if you take and pick some numbers.

Posted from my mobile device
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bb Thanks a lot.
Yes, it does makes sense now.
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