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Alex can do the work in 6 days. Work done by him in 1 day = 1/6
Bill can do the work in 10 days. Work done by him in 1 day = 1/10
Charles can do the work in 15 days. Work done by him in 1 day = 1/15

Total work done by all three of them in 1 day = 1/6 + 1/10 + 1/15 = 10/30 or 1/3
They worked together for two days. Therefore, total work done in 2 days by all of them working together = (1/3)*2 = 2/3

Alex & Bill quit after 2 days. Charles has to do the remaining work all by himself.
Total work done = 2/3
Amount of work remaining = 3 - 2/3 = 1/3

If Charles can do 1/15th of the work in 1 day working alone. So, he will be able to finish the remaining work in (1/3)/(1/15) = 5 days
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Given: Alex takes 6 days to complete a work, while Bill takes 10 days to complete the work alone. Charles takes 15 days to complete the work alone. All of them work together for 2 days. Then Alex and Bill quit.
Asked: How many days more will it take Charles to do the remaining work alone?

Work done in 2 days = 2/6 + 2/10 + 2/15 = 2(15+9+6)/90 = 2/3
Word remaining = 1/3

Time required by Charles = 15/3 = 5 days

IMO C
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I would suggest percentages..as a tool

This method is faster. We can use percentages to solve.



Alex completes 100% of work in 6 days. Bill completes 100% of work in 10 days. Charles completes 100% of work in 15 days.

In 2 days Alex completes

Lets construct a table

Days Percentage

6 100%

2 ??



Cross multiplying = 2x100/6 =33.33 %

In 2 days Alex completes =33.33% of work



Similarly

Bill completes 100% of work in 10 days.

In 2 days Bill completes 20% of the work





Charles completes 100% of work in 15 days.

In 2 days Bill completes 13.33% of the work



Total work completed = 33.33 +20 +13.33= 66.66%





Remaining work = 100-66.66 = 33.33%



Charles completes 100% of work in 15 days.

In how many days he will complete 33.33%



Percentage Days

100% 15

33.33 ??



Cross multiplying

= 33.33x15 / 100 = 5 days



Take away: You can use percentages as a tool to save time and minimize calculations.


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Alex takes 6 days to complete a work, while Bill takes 10 days to complete the work alone. Charles takes 15 days to complete the work alone. All of them work together for 2 days. Then Alex and Bill quit. How many days more will it take Charles to do the remaining work alone?

A. 7
B. 9
C. 5
D. 10
E. 2

Solution:

The rates of Alex, Bill and Charles are 1/6, 1/10 and 1/15, respectively. After two days of working together 2 x (1/6 + 1/10 + 1/15) = 2 x (5/30 + 3/30 + 2/30) = 2 x 10/30 = 2 x 1/3 = 2/3 of the job is completed. Therefore, the remaining 1/3 of the job will be completed by Charles alone in (1/3) / (1/15) = 1/3 x 15 = 5 days.

Answer: C
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