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Bunuel
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Each side is 1 (P=3, so 1+1+1)

Length from P to the Mid = 2 and From bottom to the Mid = 1

Apply Pythagoras->
a^2 + b2 = c2

In this case: c^2 - b^2 = a^2
√(length^2 - bottom to mid^2) = √(P to Mid)
√(2^2 - 1^2) = √(3).

This is the point from P to the Mid, but we need from P to Q

2 * (P to M) = PQ
2 * √(3) = 2√(3)

Answer is E
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Bunuel

The above shape is made of eight identical equilateral triangles, each having a perimeter of 3. What is the straight-line distance between points P and Q?

A. √3
B. 3
C. 4
D. 2√2
E. 2√3

Solution:

We see that the straight-line distance between points P and Q is 4 times the height of one equilateral triangle. Since an equilateral triangle has a perimeter of 3, it has side length of 1 and a height of 1/2 x 1 x √3 = √3/2 (recall that the height of an equilateral triangle is half of its side length times √3). Therefore, PQ = 4 x √3/2 = 2√3.

Answer: E
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