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A man had traveled 1/3 of the total distance of his trip when his car broke down. He finished the journey on foot, spending twenty times as long walking as he had spent driving. How many times faster was his driving speed than his walking speed?
(A) 10
(B) 12
(C) 15
(D) 20
(E) None of these
(A) 10
(B) 12
(C) 15
(D) 20
(E) None of these
22 May 2021, 00:20
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Let, the distance be x.
Travelled on car x/3 & on foot 2x/3
Time taken x and 20x
We know, s=d/t
\(S=\frac{x}{3/x}\)
=\(\frac{1}{3}\)
Again, \(s=\frac{2x}{3/20x}\)
\(=1/30\)
1/3 what fraction of 1/30
1/3×30/1=10
Answer is A
Posted from my mobile device
Travelled on car x/3 & on foot 2x/3
Time taken x and 20x
We know, s=d/t
\(S=\frac{x}{3/x}\)
=\(\frac{1}{3}\)
Again, \(s=\frac{2x}{3/20x}\)
\(=1/30\)
1/3 what fraction of 1/30
1/3×30/1=10
Answer is A
Posted from my mobile device
24 Sep 2021, 14:08
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Let's assume total distance to be 60 km
car = 60*1/3 = 20
walk = 60*2/3 = 40
formula: d = s x t
20= 20 x 1
40= 2 x 20 [takes 20 times more time]
so s1/s2 = 20/2 = 10
car = 60*1/3 = 20
walk = 60*2/3 = 40
formula: d = s x t
20= 20 x 1
40= 2 x 20 [takes 20 times more time]
so s1/s2 = 20/2 = 10
