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B
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Difficulty:
65%
(hard)
Question Stats:
51% (01:43) correct
49%
(01:53)
wrong
based on 140
sessions
History
Date
Time
Result
Not Attempted Yet
From 8 people, a team of 4 needs to be selected. How many ways are possible if two particular people do not want to be together in the team?
(A) 35
(B) 55
(C) 40
(D) 60
(E) 75
(A) 35
(B) 55
(C) 40
(D) 60
(E) 75
07 Jul 2021, 00:26
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SPHOORTHI
Say A and B do not want to be together in the team.
The number of teams with A but not B = 6C3 = 20 (we have A in the team and choosing the remaining 3 members out of 8 - A - B = 6)
The number of teams with B but not A = 6C3 = 20 (we have B in the team and choosing the remaining 3 members out of 8 - A - B = 6)
The number of teams without both A and B = 6C4 = 15 (choosing all 4 members from 8 - A - B = 6).
Total = 20 + 20 + 15 = 55.
Answer: B.
07 Jul 2021, 00:31
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Bunuel
OR:
The total number of teams possible = 8C4 = 70.
The number of teams with A and B = 6C2 = 15 (we have both A and B in the team and choosing the remaining 2 members out of 8 - A - B = 6).
The number of teams without A and B together = Total - Restriction = 70 - 15 = 55.
Answer: B.
