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07 Dec 2021, 06:30
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
51% (03:02) correct
49%
(02:37)
wrong
based on 75
sessions
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Two alloys of copper have different percentages of copper in them. The first alloy weighs 6 kg and the second one weighs 12 kg. A piece of equal weight was removed from each of the alloys. The first piece was combined with the second alloy. The second piece was combined with the first alloy. This process produced two new alloys that had the same percentage of copper. What was the weight of the piece that was removed?
(A) 1 kg
(B) 2 kg
(C) 3 kg
(D) 4 kg
(E) 5 kg
Are You Up For the Challenge: 700 Level Questions
(A) 1 kg
(B) 2 kg
(C) 3 kg
(D) 4 kg
(E) 5 kg
Are You Up For the Challenge: 700 Level Questions
07 Dec 2021, 06:40
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Use options -
E
5 kg of first to 7 kg second
1 kg of first to 5 kg of second
Ratio don’t match so it is out.
D- 4 KG
4 kg first and 8 KG second will cause the 1:2 ratio
2 kg first and 4 Kg of second will also lead to same ration of alloys. Hence answer
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E
5 kg of first to 7 kg second
1 kg of first to 5 kg of second
Ratio don’t match so it is out.
D- 4 KG
4 kg first and 8 KG second will cause the 1:2 ratio
2 kg first and 4 Kg of second will also lead to same ration of alloys. Hence answer
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07 Dec 2021, 07:08
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Bunuel
Let k be the volume of alloy removed from each alloy for exchange
Let the percentage of copper in 1st alloy be a
Let the percentage of copper in 2nd alloy be b
Weight of copper in 1st alloy would be 6a
Weight of copper in 1st alloy would be 12b
Now we have the following equation as per the scenario
(6a - ka + kb ) / 6 = (12b + ka - kb ) / 12
=> 4a + kb = 4a + ka
=> 4(a-b) = k(a-b)
=> k = 4
Option D
