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01 Mar 2022, 03:01
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (01:50) correct
20%
(01:54)
wrong
based on 234
sessions
History
Date
Time
Result
Not Attempted Yet
Tammy bikes the course of a race at 30 miles per hour, then returns home along the same route at 10 miles per hour. If the total time it takes her to travel the course and return home is 2 hours, and if the time spent turning around is negligible, what is the length, in miles, of the race course?
A) 15
B) 20
C) 25
D) 30
E) 35
A) 15
B) 20
C) 25
D) 30
E) 35
01 Mar 2022, 04:48
Kudos
Bookmarks
Let the distance of the course = d
Let the time it takes Tammy the course the first time = t
First time doing the course:
Speed = 30
Time = t
Distance = d
Formula for distance is \(Distance = Speed * Time\)
Which gives us: \(d = 30t\)
Return Trip:
Speed = 10
Time = 2-t
Distance = d
Once again using the distance formula, we get: \(d = 10(2-t)\)
\(d = 20 - 10t\) multiply through by 3
\(3d = 60 - 30t\)
Subbing in \(d = 30t\) into \(3d = 60 - 30t\) gives us:
\(3d = 60 - d\)
\(4d = 60\)
\(d = 15\)
Answer A
Let the time it takes Tammy the course the first time = t
First time doing the course:
Speed = 30
Time = t
Distance = d
Formula for distance is \(Distance = Speed * Time\)
Which gives us: \(d = 30t\)
Return Trip:
Speed = 10
Time = 2-t
Distance = d
Once again using the distance formula, we get: \(d = 10(2-t)\)
\(d = 20 - 10t\) multiply through by 3
\(3d = 60 - 30t\)
Subbing in \(d = 30t\) into \(3d = 60 - 30t\) gives us:
\(3d = 60 - d\)
\(4d = 60\)
\(d = 15\)
Answer A
01 Mar 2022, 10:04
Kudos
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Bunuel
\(2\frac{(10*30)}{(30+10)} = \frac{300}{20} = 15\), Answer will be (A)
