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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
73% (01:55) correct
27%
(02:19)
wrong
based on 143
sessions
History
Date
Time
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Not Attempted Yet
If \(r ≠ 0\) and \(r^*\) is defined as \(\frac{1}{r} - 1\), what is the value of \(-(r^*) + (r - 1)^*\)?
A. \(\frac{1}{r^2 - r}\)
B. \(\frac{r^2 + r - 1}{r^2 - r}\)
C. \(\frac{2r^2 + 2r + 1}{r - r^2}\)
D. \(\frac{2 - 3r}{r}\)
E. \(\frac{2r - 1}{r^2 - r}\)
A. \(\frac{1}{r^2 - r}\)
B. \(\frac{r^2 + r - 1}{r^2 - r}\)
C. \(\frac{2r^2 + 2r + 1}{r - r^2}\)
D. \(\frac{2 - 3r}{r}\)
E. \(\frac{2r - 1}{r^2 - r}\)
07 Apr 2022, 12:12
Kudos
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stne
I get the same answer you're getting -- I think there's a typo in answer A, and the "2" is supposed to be an "r".
General Discussion
07 Apr 2022, 11:32
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Bunuel
Let's take one expression at a time:
\(-(r^*) = - ( \frac{1}{r} -1) = \frac{r-1}{r}\)
\((r-1)^* = \frac{1}{r-1}-1 = \frac{2-r}{r-1}\)
\(\frac{r-1}{r} + \frac{2-r}{r-1}\)
\(=\frac{(r-1)^2 + r(2-r)} {r(r-1)}\)
\(=\frac{ r^2 + 1 -2r +2r- r^2}{r^2 -r}\)
\(= \frac{1}{r^2-r}\)
Not matching any of the options !
Is there a possibility option A could be \(= \frac{1}{r^2-r}\)
IanStewart Sir, could you help me here ! Thank you.
