Last visit was: 24 Apr 2026, 04:57 It is currently 24 Apr 2026, 04:57
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 24 Apr 2026
Posts: 109,811
Own Kudos:
810,950
 [12]
Given Kudos: 105,869
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,811
Kudos: 810,950
 [12]
In a class, 60% of students play soccer or basketball. If 10% play bot 18 Apr 2022, 04:15
1
Kudos
Add Kudos
10
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

55% (hard)

Question Stats:

66% (01:52) correct 34% (02:20) wrong based on 361 sessions

History

Date
Time
Result
Not Attempted Yet
In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays only one of the sports?

A. 0.2
B. 0.3
C. 0.4
D. 0.5
E. 0.6
ShowHide Answer
Official Answer
D
Most Helpful Reply
User avatar
KarishmaB
User avatar
Joined: 16 Oct 2010
Last visit: 23 Apr 2026
Posts: 16,442
Own Kudos:
79,400
 [5]
Given Kudos: 485
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,442
Kudos: 79,400
 [5]
In a class, 60% of students play soccer or basketball. If 10% play bot 28 Apr 2022, 23:29
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays only one of the sports?

A. 0.2
B. 0.3
C. 0.4
D. 0.5
E. 0.6
Show more

Say the class has 100 students. 60 play soccer or basketball. 10 play both.
Attachment:
Screenshot 2022-04-29 at 11.54.38.png
Screenshot 2022-04-29 at 11.54.38.png [ 30.12 KiB | Viewed 4480 times ]
Then number of people lying in yellow, green or blue regions are 60. We know that 10 lie in the green region.
Then number of people lying in the yellow or blue regions are 50. They are the ones who play either only soccer or only basketball.

50% students play only sport hence probability that the chosen student plays only one of these sports is 0.5
General Discussion
User avatar
Dragongirl24
User avatar
Tuck School Moderator
Joined: 13 Mar 2019
Last visit: 15 Feb 2026
Posts: 125
Own Kudos:
50
Given Kudos: 179
Location: India
GMAT 1: 540 Q38 V21
GRE 1: Q158 V152
GPA: 4
GMAT 1: 540 Q38 V21
GRE 1: Q158 V152
Posts: 125
Kudos: 50
In a class, 60% of students play soccer or basketball. If 10% play bot 28 Apr 2022, 11:25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
In a class, 60% of students play soccer or basketball. If 10% play both sports and 60% do not play soccer, what is the probability that a student chosen at random from the class plays only one of the sports?

A. 0.2
B. 0.3
C. 0.4
D. 0.5
E. 0.6
Show more


can someone explain this?
User avatar
cjhyou700
User avatar
Joined: 19 Jan 2022
Last visit: 05 Jul 2023
Posts: 11
Own Kudos:
4
 [3]
Given Kudos: 66
Posts: 11
Kudos: 4
 [3]
In a class, 60% of students play soccer or basketball. If 10% play bot 28 Apr 2022, 20:46
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Assume X students in class


soccer or Basketball：0.6x
Both soccer & Basketball：0.1x

No soccer（means only basketball）：0.6*0.6x（notice：not 60% of all students，but 60% of 0.6x）
Play soccer：0.6x-0.36x=0.24x （the number includes 0.1x)

Therefore, only soccer: 0.24x-0.1x=0.14x

Only Soccer+Only Basketball = 0.36x+0.14x=0.5x The answer! Drawing a Venn diagram will help.

I hope my reasoning is clear:) Let me know if there is anything I can improve.
avatar
NidhiR
avatar
Joined: 22 Apr 2022
Last visit: 17 Jul 2022
Posts: 29
Own Kudos:
22
Given Kudos: 3
Location: India
Posts: 29
Kudos: 22
In a class, 60% of students play soccer or basketball. If 10% play bot 28 Apr 2022, 21:26
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Suppose T be total students in class

(Given) 0.4 T do not play both games.

So, T - 0.4 T = O.6 T play either Basketball or Soccer or both.

Also. (Given) 0.1 T play both games.

Therefore , play either games (only one game ) : 0.6 T - 0.1 T = 0.5 T

hence, Desired Probability = 0.5 T / T = 0.5

Hope it helps.
User avatar
Orange2020
User avatar
Joined: 19 Sep 2019
Last visit: 03 Jan 2026
Posts: 10
Given Kudos: 86
Posts: 10
Kudos: 0
In a class, 60% of students play soccer or basketball. If 10% play bot 14 Dec 2024, 15:29
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Tip: When it says 60% of students play soccer or basketball, you have to remember to subtract out the "Both" to avoid double counting.

So it's Soccer = 40
Basketball = 30
Both = 10

40+30-10 = 60
User avatar
jsousa
User avatar
Joined: 16 Oct 2023
Last visit: 19 Mar 2026
Posts: 4
Given Kudos: 6
Posts: 4
Kudos: 0
In a class, 60% of students play soccer or basketball. If 10% play bot 10 Nov 2025, 07:25
Kudos
Add Kudos
Bookmarks
Bookmark this Post
For two sets, P(S∪B) = P(S)+P(B)−P(S∩B) Note: 60% do not play soccer → so P(S)=1−0.6 = 0.4 and we know: 0.6 = 0.4+P(B)−0.1

So: P(S) = 0.4, P(B)=0.3 and P(S∩B) = 0.1

“Only one sport” means either soccer but not basketball, or basketball but not soccer.
Then, P(only one) = P(S)+P(B)−2P(S∩B) => P(only one) = 0.4+0.3−2(0.1) = 0.5
Moderators:
Bunuel
Math Expert
109811 posts
Krunaal
Tuck School Moderator
853 posts