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x= 49 or 140 or ....
If x= 49 then 2x=98

98/13 Remainder= 7

Ans B

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Bunuel
When a positive integer x is divided by 91, the remainder is 49. What is the remainder when 2x is divided by 13 ?

A. 0
B. 7
C. 10
D. 12
E. 49
The smallest value of \(x = 49\) (Say)

So, \(2x = 98\)

\(\frac{98}{7} = 13*7 + 7 \), Thus remainder will be 7, Answer must be (B) 7
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Bunuel
When a positive integer x is divided by 91, the remainder is 49. What is the remainder when 2x is divided by 13 ?

A. 0
B. 7
C. 10
D. 12
E. 49
Since 91 is divisible by 13, the remainder 49 when divided by 13 leaves 10 as remainder. 2x would leaves 2 49's leaving 20 as cumulative remainder whihc when divided by 13 again leaves a remainder 7.

Answer B.
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a doubt
n=9q + 8

I did n=9(1) + 8 = 17 and clicked (A)

how to avoid such mistakes and which logic to use to get 10 as answer?
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harjas2222

Bunuel
When a positive integer \(x\) is divided by 91, the remainder is 49. What is the remainder when \(2x\) is divided by 13 ?

A. 0
B. 7
C. 10
D. 12
E. 49


\(x\) divided by 91, yielding a remainder of 49, can be expressed as \(x = 91q + 49\). Multiplying by 2 gives: \(2x = 2*91q + 98\). This can be rewritten as \(2x = 13*(14q + 7) + 7\). The first term, \(13*(14q + 7)\), is divisible by 13, and the last term, 7, when divided by 13, gives a remainder of 7.

Alternatively, we can reason as follows: Since a PS question can have only one correct answer, then considering one particular case which satisfies the conditions given must also yield the correct answer. If \(x\) divided by 91 yields a remainder of 49, then \(x\) can be 49. In this case, \(2x=98\), and 98 divided by 13 leaves a remainder of 7: \(98 = 13*7 + 7\).


Answer: B
a doubt
n=9q + 8

I did n=9(1) + 8 = 17 and clicked (A)

Your doubt is not clear. Please review the solution above carefully and elaborate on what exactly is confusing for you.
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